What is the amount of heat, in Sl units, necessary to melt 1 lb of ice?

Physics

1 answer:

likoan [24]3 years ago

3 0

Answer:

Heat required to melt 1 lb of ice is 151.469 KJ

Explanation:

We have given mass of ice = 1 lb

We know that 1 lb = 0.4535 kg

Latent heat of fusion for ice =334 KJ/kg

Amount if heat for fusion of ice is given by

$Q=mL$ , here m is mass of ice and L is latent heat of fusion

So heat $Q=mL=0.4535\times 334=151.469kj$

So heat required to melt 1 lb of ice is equal to 151.469 KJ

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There is a missing data in the text of the problem: the current drawn is 0.5 A (found on internet)

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leonid [27]

Answer:

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