For this use the formula:
d = Vo * t - (at^2) / 2
Clearing t:
t = d/(v + 0.5*a)
Replacing:
t = 5 m / (7.2 m/s + 0.5 * (-1.1 m/s²)
Resolving:
t = 5 m / (7.2 m/s + (-0.55 m/s²)
t = 5 m / 6.65 m/s
t = 0.75 s
Result:
The time will be <u>0.75 seconds.</u>
That n2 = 2*n1. That is, the index of refraction is twice as big in medium 2 since v=c/n
1) d = V*t >>>as you double the av. speed the distance become doubled.
2) after you draw the victors you will find the total displacement = 1 meter to the left.
3) V =d/t =( 8km)/(1.25hr) = 6.4km/hr
Answer:
This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant.
U = (1/2)kx^2
U = (1/2)(5.3)(3.62-2.60)^2
U = 2.75706 J
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Explanation:
