bonsoir, je peux vous aider avec les maths laissez-moi comprendre merci
As per Einstein's relation of relativity

here we know that


now here we know that

now from above equation mass of the muon is given as


now for the momentum of muon we can use



so above is the momentum of muon
Answer: 52%
Explanation:
1W = 1 J/s
motor input is 10000 J/s
Potential energy change
PE = 955(9.81)(25.0) = 234,213.75
power needed to change the PE in that time
P = 234,213.75/ 45 = 5,204.75 Watts
motor is 5204.75 / 10000 = 0.520475 or 52% efficient
True it was thought of as an advantage