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Rashid [163]
3 years ago
6

Until recently a number of professions were prohibited from advertising. In 1977, the U.S. Supreme Court ruled that prohibiting

doctors and lawyers from advertising violated their right to free speech. The paper "Should Dentists Advertise?" Journal of Advertising Research, June 1982) compared the attitudes of 101 consumers and 124 dentists to the questions "I favor the use of advertising by dentists to attract new patients". Determine whether the two groups differed in their attitudes toward advertising.
Group Strongly Agreed Agree Neutral Disagree Strongly disagree
Cosumers 34 47 9 6 5
Dentists 9 18 23 28 46
Mathematics
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

the two groups differed in their attitudes toward advertising, significantly

Step-by-step explanation:

given that until recently a number of professions were prohibited from advertising. In 1977, the U.S. Supreme Court ruled that prohibiting doctors and lawyers from advertising violated their right to free speech. The paper "Should Dentists Advertise?" Journal of Advertising Research, June 1982) compared the attitudes of 101 consumers and 124 dentists to the questions "I favor the use of advertising by dentists to attract new patients".

Hypotheses would be

H-0: the groups do not differ

H-a: The two groups differ significantly

(two tailed chi square test)

Observed      

Group Strongly agree Agree Neutral Disagree Strongly disagree Total

     

Consumers 34 47 9 6 5 101

Dentists 9 18 23 28 46 124

     

Expected is calculated as row total * column total / grand total for each cell

chi square = (obs - exp)^2/Exp for each cell added

chi square = 79.2716

rxc 5x2

df = 4x1 =4

p value <0.00001

Since p < alpha say 0.01, we reject null hypothesis.

the two groups differed in their attitudes toward advertising, significantly

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Hello, 

x= amount of flour that she poured in the canister

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melisa1 [442]

Answer:

For the 99th percentile, we have X = 206 seconds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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In this problem, we have that:

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Value of X when Z has a pvalue of 0.99. So we use Z = 2.325

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