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Rashid [163]
3 years ago
6

Until recently a number of professions were prohibited from advertising. In 1977, the U.S. Supreme Court ruled that prohibiting

doctors and lawyers from advertising violated their right to free speech. The paper "Should Dentists Advertise?" Journal of Advertising Research, June 1982) compared the attitudes of 101 consumers and 124 dentists to the questions "I favor the use of advertising by dentists to attract new patients". Determine whether the two groups differed in their attitudes toward advertising.
Group Strongly Agreed Agree Neutral Disagree Strongly disagree
Cosumers 34 47 9 6 5
Dentists 9 18 23 28 46
Mathematics
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

the two groups differed in their attitudes toward advertising, significantly

Step-by-step explanation:

given that until recently a number of professions were prohibited from advertising. In 1977, the U.S. Supreme Court ruled that prohibiting doctors and lawyers from advertising violated their right to free speech. The paper "Should Dentists Advertise?" Journal of Advertising Research, June 1982) compared the attitudes of 101 consumers and 124 dentists to the questions "I favor the use of advertising by dentists to attract new patients".

Hypotheses would be

H-0: the groups do not differ

H-a: The two groups differ significantly

(two tailed chi square test)

Observed      

Group Strongly agree Agree Neutral Disagree Strongly disagree Total

     

Consumers 34 47 9 6 5 101

Dentists 9 18 23 28 46 124

     

Expected is calculated as row total * column total / grand total for each cell

chi square = (obs - exp)^2/Exp for each cell added

chi square = 79.2716

rxc 5x2

df = 4x1 =4

p value <0.00001

Since p < alpha say 0.01, we reject null hypothesis.

the two groups differed in their attitudes toward advertising, significantly

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9966 [12]

Answer:

\mathrm{26.\qua\:H\quad\:2 \dfrac{ 1  }{ 4  }\qua\:mi}

\mathrm{27.\qua\:D\quad\: 9\dfrac{ 1  }{ 8  }\qua\:lb}

\mathrm{28.\qua\:H\quad\:14.6}

\mathrm{29.\qua\:C\quad\:25\%}

\mathrm{30.\qua\:J\quad\:33.912\qua\ ft^{3} }

Step-by-step explanation:

26.

\mathrm{\dfrac{ 3  }{ 4  }\:mile\:per\:one\:hour}

\mathrm{To\:find\:how\:far\:Jet's\:cousin\:can\:walk\:in\:3\:hours\:,\:we\:multiply\:\dfrac{ 3  }{ 4  }\:by\:3}

3 \times   \dfrac{ 3  }{ 4  }

\mathrm{Express\: 3 \times   \left(  \dfrac{ 3  }{ 4  }    \right)\:as\:a\:singe\:fraction}

\dfrac{ 3 \times  3  }{ 4  }

\mathrm{Multiply\:3\:and\:3\:to\:get\:9}

\dfrac{ 9  }{ 4  }

\mathrm{Convert\:\dfrac{ 9  }{ 4  }\:to\:a\:mixed\:number}

2 \dfrac{ 1  }{ 4  }

\mathrm{So\:she\:can\:walk\:2 \dfrac{ 1  }{ 4  }\:miles\:in\:3\:hours}

27.

\mathrm{Since\:we\:want\:to\:find\:how\:many\:pounds\:both\:pumpkins\:weigh\:together,\:we\:have\:to\:add.}

5 \dfrac{ 3  }{ 4  }  +3 \dfrac{ 3  }{ 8  }

\mathrm{Turn\:both\:mixed\:fractions\:into\:improper\:fractions}

\dfrac{ 23  }{ 4  }  + \dfrac{ 27  }{ 8  }

\mathrm{Least\:common\:multiple\:of\:4\:and\:8\:is\:8}

\mathrm{Multiples\:of\:4}:\quad4,8,12,16,20

\mathrm{Multiples\:of\:8}:\quad8,16,24,32,40

\dfrac{ 23  }{ 4  }  + \dfrac{ 27  }{ 8  }

\mathrm{Convert\:  \dfrac{ 23  }{ 4  }   \:and\:  \dfrac{ 27  }{ 8  }   \:to\:fractions\:with\:denominator\:8}

\dfrac{ 23 \times  2  }{ 4 \times  2  }  + \dfrac{ 27  }{ 8  }

\mathrm{Simplify}

\dfrac{ 46  }{ 8  }  + \dfrac{ 27  }{ 8  }

\mathrm{Since\:  \dfrac{ 46  }{ 8  }\:and\:\dfrac{ 27  }{ 8  }\:have\:the\:same\:denominators,\:add\:them\:by\:adding\:their\:numerators}

\dfrac{ 46+27  }{ 8  }

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\dfrac{ 73  }{ 8  }

\mathrm{Convert\:\dfrac{ 73  }{ 8  }\:to\:a\:mixed\:number}

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28.

Since the question is asking us "How many more miles did Alyce travel than Jason", we have to subtract the miles Jason traveled from the miles Alyce traveled.

29.193-14.593

\mathrm{Subtract\:14.593\:from\:29.193\:to\:get\:14.6}

14.6

\mathrm{Alyce\:traveled\:14.6\:more\:miles\:than\:Jason}

29.

For this question, we must find "10 is what percent of 40"

The equation for this is:

\dfrac{ 10  }{ 40  }   \times  100

\mathrm{Simplify\:  \dfrac{ 10  }{ 40  }   \:to\:  \dfrac{ 1  }{ 4  }   }

\dfrac{ 1  }{ 4  }   \times  100

\mathrm{Multiply\:  \dfrac{ 1  }{ 4  }\:and\:100\:to\:get\:  \dfrac{ 100  }{ 4  }   }

\dfrac{ 100  }{ 4  }

\mathrm{Divide\:100\:by\:4\:to\:get\:25}

25

\mathrm{So\:she\:recieved\:a\:25\%\:off\:discount}

To check if this is correct, you can do the following below:

What is 25 percent (%) off $40?

Use the formula and replace the given values:

Amount Saved = Original Price x Discount % / 100. So,

Amount Saved = 40 x 25 / 100

Amount Saved = 1000 / 100

Amount Saved = $10

In other words, a 25% discount for an item with original price of $40 is equal to $10

 

30.

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\mathrm{Current\:compacity} =  90 \%   \times  37.68

\mathrm{Turn\:90\%\:into\:a\:decimal}

\mathrm{Current\:compacity} =  0.9   \times  37.68

\mathrm{Multiply\:0.9\:and\:37.68\:to\:get\:33.912}

33.912

\mathrm{The\:current\:compacity\:of\:the\:drum\:is\:33.912\:ft^{3} }

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Using the graph below, find r(-3) please
ruslelena [56]

Considering the given graph, it is found that the numeric value of the function r(x) at x = -3 is of 2.

<h3>How to find the numeric value of a function given it's graph?</h3>

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More can be learned about the numeric value of a function at brainly.com/question/14556096

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