Given:
The quadratic equation is:


To find:
The value of k and
.
Solution:
We have,
...(i)
Putting
, we get




Putting
in (i), we get

Splitting the middle term, we get




Here,
and
.
Therefore, the required values are
and
.
Answer:
One solution.
Step-by-step explanation:
To determine the number of possible solutions for a triangle with A = 113° , a = 15, and b = 8, we're going to use the law of sines which states that: "<em>When we divide side a by the sine of angle A it is equal to side b divided by the sine of angle B, and also equal to side c divided by the sine of angle C</em>".
Using the law of sines we have:


Solving for B, we have:

∠B = 29.4°
Therefore, the measure of the third angle is: ∠C = 37.6°
There is another angle whose sine is 0.4909 which is 180° - 29.4° = 150.6 degrees. Given that the sum of all three angles of any triangle must be equal to 180 deg, we can't have a triangle with angle B=113° and C=150.6°, because B+C>180.
Therefore, there is one triangle that satisfies the conditions.
Im pretty sure its two but you might wanna double check... let me know
4 units wide........................
Answer:
.8
Step-by-step explanation: