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xeze [42]
4 years ago
9

A student measures the maximum speed of a block undergoing simple harmonic oscillations of amplitude A on the end of a single id

eal spring with spring constant k. The single spring is then replaced with 3 identical springs (in series) with the same spring constant k. If the same block undergoes SHM with the same amplitude before, by what factor does the maximum speed change?
Physics
1 answer:
barxatty [35]4 years ago
7 0

Answer:

Explanation:

Given

Amplitude of oscillation is A

spring constant k

suppose m is the mass of block so its natural frequency of oscillation is given by

\omega _n=\sqrt{\frac{k}{m}}

v_{max}=A\omega =A\cdot \sqrt{\frac{k}{m}}

When three identical springs is connected in series

k_{effectice}=\frac{k}{3}

Natural Frequency becomes

\omega _n=\sqrt{\frac{k}{3m}}

Thus maximum speed with Amplitude A is

v'_{max}=A\cdot \sqrt{\frac{k}{3m}}

so by a factor of \frac{1}{\sqrt{3}} maximum velocity is changed      

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Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

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Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

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Using formula of moment of inertia

I=I_{1}+I_{2}

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Put the value into the formula

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