Question

At a certain distance, the sound intensity level of a dog's bark is 59 dB. At that same distance, the sound intensity of a rock concert is twenty thousand times that of the dog's bark. What is the sound intensity level of the rock concert

Answer 1

Answer:

102 dB    

Explanation:

Intensity level is given by:

$I(dB)=10log\frac{I}{I_o}$

$59=10log\frac{I_d}{I_o}\\I_d=10^{5.9}I_o$

$I_r=2\times10^4I_d=2\times10^4\times10^{5.9}I_o$

$I_r(dB)=10log\frac{I_r}{I_o}\\=10log\frac{2\times 10^{9.9}I_o}{I_o}=10\times10.2\\=102 dB$