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VARVARA [1.3K]
3 years ago
7

When multiplying decimals what do you have to analyze​

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer: Line up the numbers on the right  do not align the decimal points. Starting on the right, multiply each digit in the top number by each digit in the bottom number, just as with whole numbers.

Step-by-step explanation:

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In XYZ, what is the cosine ratio of X?
Wittaler [7]

Answer:

c) 12/15 = 4/5

Step-by-step explanation:

imagine we mirror the triangle up, so that Z is on top.

then you can clearly see that 6 is cos(X) times r (and r is then 7.5).

XY is sin(X)×7.5

and again, 7.5 is r (the line making the X angle).

so, the cosine ratio of X is

6 = cos(X)×7.5

cos(X) = 6/7.5 or then 12/15. or simplified 4/5.

4 0
3 years ago
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What is the sum of the interior angles of a square
kap26 [50]

Answer:

90

Step-by-step explanation:

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7 0
3 years ago
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Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle

So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
Use the equation to answer the following question y=(x-3(x+2)/(x+4)(x-4)(x+2)
givi [52]

Answer:

See below

Step-by-step explanation:

The given rational function is;

y=\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}

The given function is not continuous where the denominator is equal to zero.

(x+4)(x-4)(x+2)=0

The function is discontinuous at x=-4,x=4,x=-2

b) The point at x=-2 is a removable discontinuity(hole) because (x+2) is common to both the numerator and the denominator.

The point at x=-4 and x=4 are  non-removable discontinuities(vertical asymptotes)

c) The equation of the vertical asymptotes are x=-4 and x=4

To find the equation of the horizontal asymptote, we take limit to infinity.

\lim_{x\to \infty}\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}=0

The horizontal asymptote is y=0

8 0
3 years ago
Use the order of operations to simplify 8.6 - 4.2+ 3/10<br>​
SVETLANKA909090 [29]

Answer:

4.7

Step-by-step explanation:

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