Question

HELP WITH THESE QUESTIONS PART 2... 1 Question

Answer 1

Step-by-step explanation and Answers:

$(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}})$ is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = $\sqrt{10}$

sin = $\frac{opposite}{hypotenuse}$ = $\frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{3\sqrt{10}}{10}$

cos =  $\frac{adjacent}{hypotenuse}$ = $\frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{\sqrt{10}}{10}$

tan = $\frac{opposite}{adjacent}$ = $\frac{3}{1}$ = 3

csc = $\frac{hypotenuse}{opposite}$ = $\frac{\sqrt{10}}{3}$

sec = $\frac{hypotenuse}{adjacent}$ = $\frac{\sqrt{10}}{1}$ = $\sqrt{10}$

cot = $\frac{adjacent}{opposite}$ = $\frac{1}{3}$