Answer:
The answer is 63, but there is no option of the answer
Step-by-step explanation:
Please give me brainliest ;)
I think it would be 4.
8 breaks down to 4(2) and 12 breaks down to 4(3). Let me know if that helps!
The graph shows a slope 7/10, which is 0.7. Only 8/11 (=0.72727) is greater than 0.7, so the answer is y=(8/11)x
Answer:
a) P=0.558
b) P=0.021
Step-by-step explanation:
We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.
The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:


b) The approximate probability that at least 9 carry the gene is:



<h3><u>
Answer:</u></h3>
<h3><u>
Step-by-step explanation:</u></h3>
We know that:
- <u>Trapezoid ABCD has one side that is 25 unit. </u>
- <u>The other 3 sides (AB, BC, and CD) are 12 units. </u>
- <u>EF = 6 units</u>
- <u>EH = 12.5</u>
- <u>Trapezoid ABCD is congruent to Trapezoid EFGH</u>
<em>If the 3 sides of the trapezoid ABCD are the same sides, then side EF, FG, GH must be of the same length because of congruence. The value of FG and GH must be the same length as EF. We can clearly see in the picture that EF is 6 units. Hence, EF is 6 units, FG is 6 units, and GH is 6 units. The work of the perimeter is shown below.</em>
<u>Work</u>
- => 6(3) + 12.5
- => 18 + 12.5
- => <u>30.5 units</u>
Hence, the perimeter of EFGH is 30.5 units.
