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Komok [63]
3 years ago
12

Robert plans to make a box-and-whisker plot of the following set of data. 27, 14, 46, 38, 32, 18, 21 Which of the following shou

ld Robert's box-and-whisker plot look like?

Mathematics
1 answer:
Simora [160]3 years ago
7 0
To make a box and whisker plot, you need to draw a number line that would be able to represent all the values in the data (look at your lowest and highest numbers).

You will need to graph the following 5 points on your number line (median, lower quartile, lower extreme, upper quartile, and upper extreme).

Create a box around the quartiles and extend the lines to the extremes.
See the picture I have attached for the box and whisker box for this data set.

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Which equation choice could represent the graph shown below?<br> Y
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The  lastt one

Step-by-step explanation:

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Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
2 years ago
Simplify the following expression:
Keith_Richards [23]

Answer:

Step-by-step explanation:

-2(2)-1+1(1)-1(-1)

Do multiplication

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Now add/subtract

-5+2

-3

6 0
3 years ago
Answer fast please!
zepelin [54]
I believe it's A but it's not exactly clear
6 0
3 years ago
Read 2 more answers
A paddleboat can move at a speed of 4 ​km/h in still water. The boat is paddled 12 km downstream in a river in the same time it
Bas_tet [7]

Answer:

Speed of the river = \frac{4}{3} km per hour

Step-by-step explanation:

Speed of the boat in still water = 4 km per hour

Let the speed of the river = v km per hour

Speed of the boat upstream = (4 - v) km per hour

Time taken to cover 6 km = \frac{\text{Distance}}{\text{Speed}}

                                           = \frac{6}{4-v} hours

Speed of the boat downstream = (4 + v) km per hour

Time taken to cover 12 km = \frac{12}{4+v} hours

Since, time taken by the boat in both the cases is same,

\frac{6}{4-v}= \frac{12}{4+v}

6(4 + v) = 12(4 - v)

24 + 6v = 48 - 12v

12v + 6v = 48 - 24

18v = 24

v = \frac{24}{18}

v = \frac{4}{3} km per hour

3 0
3 years ago
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