The solution to the system of equation are x=2, y=0, z=6
<h3>System of equations</h3>
System of equations are equations that contains unknown variables.
Given the equations
3x+y+2z=8
8y+6z=36
12y+2z=12
From equation 2 and 3
8y+6z=36 * 1
12y+2z=12 * 3
______________
8y+6z=36
36y+6z= 36
Subtract
8y - 36y = 36 - 36
-28y =0
y = 0
Substitute y = 0 into equation 2
8(0)+6z=36
6z = 36
z = 6
From equation 1
3x+y+2z =8
3x + 0 + 2(6) = 8
3x = 8 - 12
3x = 6
x = 2
Hence the solution to the system of equation are x=2, y=0, z=6
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There are 4/7 boys, so there are 3/7 girls.
Let the total number of children be x.
4/7x = 8
1/7x = 8 ÷ 4
1/7x = 2
3/7x = 2 x 3
3/7x = 6
There are 6 girls.
No he cannot bc 61 is an odd number
V = a * b * c
V = 30
a = 5
b = 2
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
c = 3
