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Naddika [18.5K]
3 years ago
13

can someone write a subtraction problem that has a mixed numbers and requires a number remaining. PLEASE AND THANK U

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0
1/2 -3/6 is equal to 0 because 1/2 is equal to 1/2
You might be interested in
division equation where 13 is quotient with the dividend a whole number and a unit fraction is the divisor
lys-0071 [83]

The division equation that has a quotient of 13 is 1/1/13 = 13

<h3>How to determine the equation?</h3>

The given parameters are:

  • Quotient = 13
  • Dividend = Whole number
  • Divisor = Unit fraction i.e. 1/n where n is an integer.

A division equation is represented as:

Dividend/Divisor = Quotient

Substitute 13 for the Quotient

Dividend/Divisor = 13

Recall that:

Unit fraction = 1/n

So, we have:

Dividend/1/n = 13

Let n = 13.

So, we have:

Dividend/1/13 = 13

This gives

13 * Dividend = 13

Divide both sides by 13

Dividend = 1

So, we have:

1/1/13 = 13

Hence, the division equation is 1/1/13 = 13

Read more about division equations at:

brainly.com/question/1622425

#SPJ1

3 0
2 years ago
One student can paint a wall in 16 minutes. Another student can paint the same wall in 24 minutes. Working together, about how l
Mazyrski [523]
Let's look at work rates per minute.

Together they can paint the wall in x minutes.
Working together, in 1 minute, they do 1/x of the job.

The student who paints the wall in 16 minutes does 1/16 of the job in 1 minute.
The student who paints the wall in 24 minutes does 1/24 of the job in 1 minute.
Together, they do 1/16 + 1/24 of the job in 1 minute, but from above, we see that together, they do 1/x of the job in 1 minute, so 1/16 + 1/24 must equal 1/x. That gives us our equation.

1/16 + 1/24 = 1/x

1/16 * 3/3 + 1/24 * 2/2 = 1/x

3/48 + 2/48 = 1/x

5/48 = 1/x

x = 48/5 = 9.6

Answer: It takes them 9.6 minutes, or about 10 minutes to do the job together.


5 0
3 years ago
Evaluate<br> 3.r” + 2y when r<br> 3 and y<br> 3
aleksandr82 [10.1K]

Answer:

first 2x3= 6

3.3 + 6 = 9,3

answer should be 9,3

3 0
3 years ago
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
May I please receive help?
Yuki888 [10]

Answer:

9.2 ft

Step-by-step explanation:

The shape is a triangle, the 11 ft is your hypotenuse

You need to use the Pythagorean Theorem!

a^2 + b^2 = c^2 (solve for a, the missing length that they ask for)

so --->

a^2 + (6^2) = 11^2

      a^2 + 36 = 121

             ~subtract 36 to the right side~

               a^2 = 85

now find the square root of 85:

               a = 9.21954

        round it to the nearest tenth:

                   a = 9.2

final answer: 9.2 ft

hope this helpsss

3 0
2 years ago
Read 2 more answers
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