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erica [24]
3 years ago
10

4x+3y=14 and 6x-5y=40

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0
Let's solve this system using elimination by addition/subtraction.

Note that if we mult. the first equation by 5, we get 20x + 15y = 70, and if we mult. the 2nd eqn by 3, we get 18x - 15y = 120.

Adding these two results together eliminates the y terms:  38x = 190. Then
x=5.

Subbing 5 for x in the 1st equation:  4(5) + 3y = 14
                                                            20  + 3y = 14
                                                                    3y= -6
                                                                      y = -2

Then the solution is (5,-2).  Check this by subbing 5 for x and -2 for y in the 2nd equation.  Is the second equation then true?
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Using a calculator,

P(1739

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