Answer:
Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.Domain: [4,∞),{x|x≥4}[4,∞),{x|x≥4}Range: [0,∞),{y|y≥0}
Answer:
1r
Step-by-step explanation:
(5r-4)(2r-6r+4)
1(5r-4)+1(2r-6r+4)
5r-4+2r-6r+4
5r+2r-6=1r
1r-4+4
-4+4=0
1r
Answer:

Step-by-step explanation:
The function that we have to study in this problem is

The domain of a function is defined as the set of all the possible values of x that the function can take.
For a square-root function, there are some limitations to the possible value of the argument in the root.
In particular, the argument of a square root must be equal or greater than zero, because the square root of a negative number is not defined.
Therefore, in this case, we have to set the following condition for the domain:

And by solving, we get

which means that the domain of this function is all real numbers equal or greater than 5.
The answer of your question is 4x +6y = - 5
Three equivalent ratios of 48:36 are 12:9 ,24:18 ,16:12.