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Neko [114]
3 years ago
9

Solve the following multiplication and division problems.

Mathematics
2 answers:
stealth61 [152]3 years ago
6 0

Answer:

To solve these problems, we just need to multiply or divide.

To solve problem c and d, we need to transform all units to the same, and then operate.

<h3>a.</h3>

10yd \times 3yd = 30yd^{2}

Remember that yd \times yd = yd ^{2}

<h3>b.</h3>

15ft \times 18 ft = 270 ft^{2}

<h3>c.</h3>

13yd \ 2ft \ 6in \times 15

To solve this one, we need to transform all lengths to yards. We know that 1 yard equals 3 feet and 1 feet equals 12 inches. So,

(13yd + 2ft\frac{1yd}{3ft}+6in\frac{1yd}{36in}  \times 15\\(13yd+0.67yd+0.17yd) \times 15 =207.6yd

<h3>d.</h3>

(198yd^{2} + 8ft^{2}) \times 7 \\(198yd^{2} + 8ft^{2}\frac{1yd^{2} }{9ft^{2} }) \times 7 \\(198yd^{2} +0.89yd^{2}) \times 7 =1,392.23 yd^{2}

pshichka [43]3 years ago
4 0

Answer:


Step-by-step explanation:

a. 10 yd.×3 yd.=30 square yards;

b. 15 ft.×18 ft.=279 square feets;

c. 13 yd.=13×3 ft.=39 ft.=39×12 in.=468 in., 2 ft. 6 in.=2×12+6 in.=30 in., then 13 yd. 2 ft. 6 in.×15=498 in. × 15=7470 in.;

d. 198 sq. yd.=198 ×9 sq. ft.=1782 sq. ft.

198 sq. yd. 8 sq. ft. =1782+8 sq. ft.=1790 sq. ft.

Then 1790 sq. ft. × 7=12530 sq. ft.

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