False. Heat radiation from the sun cannot reach Earth, we cannot receive TV or GPS signals from satellites, and we cannot detect the light from distant stars.
Oh, wait . . .
Given Information:
Inlet Temperature of hot air= Th₁ = 450K
Exit Temperature of hot air = Th₂ = 350K
Inlet Temperature of cold air = Tc₁ = 300K
Volume flow rate of hot air = vh = 0.02 m³/s
Volume flow rate of cold air = vc = 1 m³/s
Required Information:
Exit Temperature of cold air= Tc₂ = ?
Answer:
Exit Temperature of cold air = Tc₂ = 302 °C
Explanation:
In a heat exchanger, the cold air absorbs heat that is lost by the hot air,
Heat absorbed by cold air = Heat lost by hot air
Therefore, the exit temperature of the cold air is 302 °C or 575K
Note:
m = ρv
Where ρ is density of air and v is the volume flow rate and m is the mass flow rate.
cp is the specific heat capacity of air.
Answer: 2mph
Explanation:
In relative vector : Considering objects A and B
a) when two objects are moving in the same direction
Vab = Va + Vb
b) when two objects are moving in an opposite direction
Van = Va - Vb
Hence, this rule will be applied.
Speed upstream = ( 33-v ) opposite direction of the current
Downstream = ( 33+v ) same direction with the current
Distance = speed × time
Time upstream = 35/60
Time downstream = 31/60
From the formulae distance = speed × time
Upstream = ( 33-v ) × 35/60 ............ 1
Downstream = ( 33+V ) × 31/60 .............. 2
Equate 1 and 2
33-v) ×35/60 = 33+V) ×31/60
Multiply both side by 60
1155-35v = 1023+31v
1155-1023 = 31+35
132 = 66v
V = 2mph
Answer:
c
Explanation:
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