(a) What is the effective resistance of the diode when it was forward biased by 0.7 volts? ( Reff =V/I )
1 answer:
Answer:
a) Effective resistance when diode was forward biased = 0 Ω
b) Effective resistance when diode was reverse biased = ∞ Ω
Explanation:
Please refer attached characteristic curve for diode.
a) As per the characteristic curve, when the diode was forward biased by 0.7 Volt theoretically infinite current was flowing across the diode.
Hence effective resistance for the diode in forward biased = = 0 Ω
b) As per the characteristic curve, when the diode was reversed biased by 0.7 Volt theoretically zero (0 amp) current was flowing across the diode.
Hence effective resistance for the diode in forward biased = = ∞ Ω
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Answer:
The index of refraction of the liquid is n = 1.33 equivalent to that of water
Explanation:
Solution:-
- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.
- The index of refraction is material property and proportional to density of the material.
- The denser the material the slower the light will move through associated with considerable diffraction angles.
- The lighter the material the faster the light pass through the material without being diffracted as much.
- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.
- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.
- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.
- The light passes through a liquid with speed v = 2.25*10^8 m/s :
- The index of refraction of the liquid is n = 1.33 equivalent to that of water.