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3 years ago

Electromagnetic waves can travel through empty space true or false

1 answer:

6 0

False. Heat radiation from the sun cannot reach Earth, we cannot receive TV or GPS signals from satellites, and we cannot detect the light from distant stars.
Oh, wait . . .

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A 7.0kg skydiver is descending with a constant velocity

Vikentia [17]

Answer:

The air resistance on the skydiver is 68.6 N

Explanation:

When the skydiver is falling down, there are two forces acting on him:

- The force of gravity, of magnitude $mg$ , in the downward direction (where m is the mass of the skydiver and g is the acceleration due to gravity)

- The air resistance, $R$ , in the upward direction

So the net force on the skydiver is:

$F=mg-R$

where

m = 7.0 kg is the mass

$g=9.8 m/s^2$

According to Newton's second law of motion, the net force on a body is equal to the product between its mass and its acceleration (a):

$F=ma$

In this problem, however, the skydiver is moving with constant velocity, so his acceleration is zero:

$a=0$

Therefore the net force is zero:

$F=0$

And so, we have:

$mg-R=0$

And so we can find the magnitude of the air resistance, which is equal to the force of gravity:

$R=mg=(7.0)(9.8)=68.6 N$

6 0

4 years ago

A block of mass 2 kg is launched by compressing a spring of force constant 1200 N/m. The block slides on a frictionless surface,

SVEN [57.7K]

Answer:

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Explanation:

3 0

3 years ago

In a water molecule, which atom has the strongest attraction for shared electrons?

ra1l [238]

Oxygen... Hope this Warner helps

6 0

3 years ago

Read 2 more answers

The attractive or repulsive force between objects is called

Romashka [77]

The answer to this is electric force. Hope it helps

3 0

3 years ago

Calculate the approximate force on a square meter (1.00 m3) of sail, given the horizontal velocity of the wind is 6.00 m/s paral

KiRa [710]

Answer:

The force exerted on square meter of cubic sail is F = 15.3 N

Explanation:

Given:-

- The face area of cubic sail, A = 1 m^2

- The velocity at frontal face, v1 = 6.0 m/s

- The velocity at back face, v2 = 3.5 m/s

- The density of air. ρ = 1.29 kg/m^3

Find:-

Calculate the approximate force on a square meter (1.00 m3) of sail

Solution:-

- We will apply the Bernoulli's equation to the flow of air around the cubic sail. Assuming that elevation changes are negligible. The constant elevation Bernoulli's equation is:

P1 + ρ*v1^2 / 2 = P2 + ρ*v2^2 / 2

- The force (F) applied by any fluid is given by:

F = ( P2 - P1 )*A

- Re-arranging bernoulli's expression:

P2 - P1 = ρ/ 2 [ v2^2 - v1^2 ]

- Multiple the equation by area A:

A*[P2 - P1] = A*ρ/ 2 [ v1^2 - v2^2 ]

F = A*ρ/ 2 [ v1^2 - v2^2 ]

- Plug in the values:

F = (1)*(1.29/2)*[ 6^2 - 3.5^2 ]

F = 15.3 N

7 0

3 years ago