A rock is dropped from a 200 m high cliff. How long does it take to fall (a) the first 100 m and (b) the last 50 m?
The basic equation you want is:
s=at22
Solving for t:
t=2sa−−−√
We’ll assume a=9.8 , so 2a−−√=14.9−−−√≈0.4518
So, for (a)s=100 , so t=0.4518100−−−√=4.518
The total time is 0.4518200−−−√≈6.389
The time to fall 150 m is 0.4518150−−−√≈5.533
So the time to fall the last 50 m is 6.389 - 5.533 = 0.856 seconds
(
The answer is around 7.
As the acid and the base are of equal strength, they neutralize each other and the resulting solution is neutral (pH≈7).
Hope this helps you!
Answer:
option B is the correct answer
Explanation:
please follow me and Mark me brainliest please
Answer: 27.21 V
Explanation:
The <u>electric potential</u> 
due to a point charge is expressed as:
Where:
is the <u>electric constant</u>
is the <u>electric charge of the hydrogen nucleus</u>, which is positive
is the <u>distance</u>
Rewritting the equation with the known values:
Finally:
Answer:
the angular velocity of the car is 12.568 rad/s.
Explanation:
Given;
radius of the circular track, r = 0.3 m
number of revolutions per second made by the car, ω = 2 rev/s
The angular velocity of the car in radian per second is calculated as;
From the given data, we convert the angular velocity in revolution per second to radian per second.
Therefore, the angular velocity of the car is 12.568 rad/s.
