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krok68 [10]
3 years ago
5

What factor affects weight( what force causes weight to change)

Physics
1 answer:
Alex Ar [27]3 years ago
3 0

Answer:

Gravitational force affects weight, weight changes with change in gravity

Hope it helped u,

mark as the brainliest

^_^

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5.
igor_vitrenko [27]

Answer:

a=40\ m/s^2

Explanation:

Given that,

Initial speed of a shuttlecock, u = 30 m/s

Final speed of the shuttlecock, v = 10 m/s

Time, t = 0.5 s

We need to find its average acceleration. The acceleration of an object is equal to the change in speed divided by time taken. It is given by :

a=\dfrac{v-u}{t}\\\\a=\dfrac{10-30}{0.5}\\\\a=-40\ m/s^2

So, the average acceleration of badminton shuttlecock is 40\ m/s^2.

3 0
3 years ago
How is the pressure of a gas related to its concentration of particles?
Nat2105 [25]
Increasing the pressure of gas is like exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume.
Hope this helps!
3 0
2 years ago
Read 2 more answers
A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. W
DENIUS [597]

Answer

given,

mass of the drop, m = 0.0014 g

speed of the drop, u = 8.1 m/s

a) Change in momentum is equal to impulse

   final velocity of the drop, v = 0 m/s

   J = m ( v - u )

   J = 0.0014 x 10⁻³ x ( 0 - 8.1 )

   J = -1.134 x 10⁻⁵ kg.m/s

impulse of the roof = - J = 1.134 x 10⁻⁵ kg.m/s

b) time, t = 0.37 m s

   impact of force = ?

  we know

     J = F x t

   1.134 x 10⁻⁵ = F x 0.37 x 10⁻³

     F =  0.031 N

the magnitude of the force of the impact is equal to F =  0.031 N

5 0
3 years ago
When does air become turbulent around a thrown ball?
kherson [118]

Answer: B (on the rough side)

Thanks for using Brainly! Vote Biden 2020

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8 0
3 years ago
27. (a) What magnification is produced by a 0.150 cm focal length microscope objective that is 0.155 cm from the object being vi
denpristay [2]

Answer:

magnification = - 30

overall magnification = -240

Explanation:

given data

Focal length of microscope objective f = 0.150 cm

Object distance from microscope objective do = 0.155 cm

magnification by eyepiece = 8 ×

to find out

What magnification is produced  and overall magnification

solution

we consider here  Image distance from microscope objective is =  di

so that

Magnification produced by objective will be = - \frac{di}{do}

so we find here  di by given equation that is

\frac{1}{do} +\frac{1}{di} = \frac{1}{f}     ..................1

\frac{1}{di} = \frac{1}{0.150} - \frac{1}{0.155}

di = 4.65 cm

so that magnification by object will be

magnification = - \frac{di}{do}

magnification = - \frac{4.65}{0.155}

magnification = - 30

and

overall magnification will be

overall magnification = magnification by objective × magnification by eyepiece   ........................2

overall magnification = -30 × 8

overall magnification = -240

7 0
3 years ago
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