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ss7ja [257]
3 years ago
11

What monatomic ions would you expect potassium (Z = 19) and bromine (Z = 35) to form?

Chemistry
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

Explanation:

Potassium ion will be formed when potassium atom loses one electron to become positively charged

K₁₉ →→  K₁₉⁺ + e⁻

Bromine ion is formed by gain of electron

Br₃₅ + e⁻ → Br₃₅⁻

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The mass numbers for two isotopes are unequal because they have different numbers of NEUTRONS.

5 0
3 years ago
Read 2 more answers
Hello!
blondinia [14]

Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

Which can be written in terms of x, according to the ICE table:

0.32=\frac{x^2}{0.015M-x}

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.015M-0.01436M=0.00064M

Regards!

5 0
2 years ago
What are the missing coefficients for the skeleton equation below? Cr(s)+Fe(NO3)2(aq)>Fe(s)+Cr(NO3)3(aq)
Stolb23 [73]

Answer:

2 Cr(s) + 3 Fe(NO3)2(aq) = 3 Fe(s) + 2 Cr(NO3)3(aq)

Explanation:

I balanced this chemical equation so that both sides are equal, meaning that the mass of reactants is equal to mass of products.

7 0
2 years ago
What are the major species in solution when solid ammonium bromate is dissolved in water?
DaniilM [7]
The major species in solution when solid ammonium bromate is dissolved in water is shown below

6 0
3 years ago
A chemist must dilute 34.3mL of 1.72mM aqueous calcium sulfate solution until the concentration falls to 1.00mM. He'll do this b
EastWind [94]

Answer:

58.9mL

Explanation:

Given parameters:

Initial volume  = 34.3mL    = 0.0343dm³

Initial concentration  = 1.72mM   = 1.72 x 10⁻³moldm⁻³

Final concentration  = 1.00mM = 1 x 10⁻³ moldm⁻³

Unknown:

Final volume  =?

Solution:

Often times, the concentration of a standard solution may have to be diluted to a lower one by adding distilled water. To find the find the final volume, we must recognize that the number of moles of the substance in initial and final solutions are the same.

   Therefore;

              C₁V₁  =  C₂V₂

where C and V are concentration and 1 and 2 are initial and final states.

        now input the variables;

                      1.72 x 10⁻³ x  0.0343 = 1 x 10⁻³  x V₂

                        V₂ = 0.0589dm³ = 58.9mL

         

4 0
3 years ago
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