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kogti [31]
3 years ago
12

2NBr3 + 3NaOH – N2 + 3NaBr + 3HBrO

Chemistry
1 answer:
Damm [24]3 years ago
3 0

Answer:

50 formula units of NBr3 will yield 75 formula units of NaBr

57 formula units of NaOH will yield 57 formula units of NaBr

Explanation:

The equation of the reaction is ;

2NBr3 + 3NaOH – N2 + 3NaBr + 3HBrO

Number of formula units of NaBr formed when 50NBr3 reacts was obtained from;

2 formula units of NBr3 yields 3 formula units of NaBr

50 formula units of NBr3 will yield 50 ×3/2 = 75 formula units of NaBr

Hence 50 formula units of NBr3 will yield 75 formula units of NaBr

Then;

Since 3 formula units of NaOH yields 3 formula units of NaBr

57 formula units of NaOH will yied 57×3/3 = 57 formula units of NaBr

Hence 57 formula units of NaOH will yield 57 formula units of NaBr

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The periodic table is a table that arranges elements based on their atomic numbers into groups and periods.

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               Group                             Other names

              1A or 1                               Alkali metals

              IIA or 2                              Alkaline earth metals

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There are 18 vertical columns divided into 8 tall groups or main groups which are 1A to O. The short groups or subgroups are from numerals 1B to VIII.

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Which particle of the atom has a negative charge?
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State whether each of the following is a molecular element molecular compound or ionic compound.
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5 0
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Based on the molecular formula, determine whether each of the following is an alkane, alkene, or alkyne. (Assume that the hydroc
stealth61 [152]

Answer:

C₃H₆ is an alkene

C₆H₁₂ is an alkene

C₈H₁₈ is an alkane

C₇H₁₂ is an alkyne

Explanation:

To determine which of the compound is alkane, alkene, or alkyne,we shall use the general formula of alkane, alkene, and alkyne. This is illustrated below:

General formula for alkane => CₙH₂ₙ₊₂

General formula for alkene => CₙH₂ₙ

General formula for alkyne => CₙH₂ₙ₋₂

For C₃H₆:

n = 3

Alkane => CₙH₂ₙ₊₂ => C₃H₂₍₃₎₊₂ => C₃H₈

Alkene => CₙH₂ₙ => C₃H₂₍₃₎ => C₃H₆

Alkyne => CₙH₂ₙ₋₂ => C₃H₂₍₃₎₋₂ => C₃H₄

Thus, C₃H₆ is an alkene

For C₆H₁₂:

n = 6

Alkane => CₙH₂ₙ₊₂ => C₆H₂₍₆₎₊₂ =>C₆H₁₄

Alkene => CₙH₂ₙ => C₆H₂₍₆₎ => C₆H₁₂

Alkyne => CₙH₂ₙ₋₂ => C₆H₂₍₆₎₋₂ => C₆H₁₀

Thus, C₆H₁₂ is an alkene

For C₈H₁₈:

n = 8

Alkane => CₙH₂ₙ₊₂ => C₈H₂₍₈₎₊₂ => C₈H₁₈

Alkene => CₙH₂ₙ => C₈H₂₍₈₎ => C₈H₁₆

Alkyne => CₙH₂ₙ₋₂ => C₈H₂₍₈₎₋₂ => C₈H₁₄

Thus, C₈H₁₈ is an alkane.

For C₇H₁₂:

n = 7

Alkane => CₙH₂ₙ₊₂ => C₇H₂₍₇₎₊₂ => C₇H₁₆

Alkene => CₙH₂ₙ => C₇H₂₍₇₎ => C₇H₁₄

Alkyne => CₙH₂ₙ₋₂ => C₇H₂₍₇₎₋₂ => C₇H₁₂

Thus, C₇H₁₂ is an alkyne.

SUMMARY:

C₃H₆ is an alkene

C₆H₁₂ is an alkene

C₈H₁₈ is an alkane

C₇H₁₂ is an alkyne

3 0
3 years ago
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