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3 years ago

2NBr3 + 3NaOH – N2 + 3NaBr + 3HBrO

Chemistry

1 answer:

Damm [24]3 years ago

3 0

Answer:

50 formula units of NBr3 will yield 75 formula units of NaBr

57 formula units of NaOH will yield 57 formula units of NaBr

Explanation:

The equation of the reaction is ;

2NBr3 + 3NaOH – N2 + 3NaBr + 3HBrO

Number of formula units of NaBr formed when 50NBr3 reacts was obtained from;

2 formula units of NBr3 yields 3 formula units of NaBr

50 formula units of NBr3 will yield 50 ×3/2 = 75 formula units of NaBr

Hence 50 formula units of NBr3 will yield 75 formula units of NaBr

Then;

Since 3 formula units of NaOH yields 3 formula units of NaBr

57 formula units of NaOH will yied 57×3/3 = 57 formula units of NaBr

Hence 57 formula units of NaOH will yield 57 formula units of NaBr

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In a mixture of hydrogen and nitrogen gases, the mole fraction of nitrogen is 0.333. If the partial pressure of hydrogen in the

notka56 [123]

Answer:

$P_T=112.4torr$

Explanation:

Hello there!

In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:

$P_{H_2}=x_{H_2}*P_T$

And can be solved for the total pressure as follows:

$P_T=\frac{P_{H_2}}{x_{H_2}}$

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