All categories

3 years ago

Classify the following as atoms or molecules. Drag the appropriate items to their respective bins. a. Mg S b. H2 SO3 c. HBr

Chemistry

1 answer:

Harman [31]3 years ago

4 0

Answer:

a) Mg and S = atoms

b) H2 SO3 = molecules

c) HBr =molecule

Explanation:

Step 1: Data given

Atoms = An atom is the smallest constituent unit of ordinary matter that constitutes a chemical element. We can find them on the periodic table.

Molecules = A molecule is an electrically neutral group of two or more atoms held together by chemical bonds.

a. Mg S = Magnesium and sulfur both are atoms, we both can find them on the periodic table

b. H2 SO3 = H2 is a molecule that contains 2 hydrogen atoms

SO3 is a molecule that contains 1 sulfur atoms and 3 oxygen atoms

c. HBr = HBr is a molecule that contains 1 hydrogen and 1 bromine atom

You might be interested in

What's an extensive property of matter

aev [14]

Answer:

Mass, Volume, Length, Moles, Energy, Number of Particles

Explanation:

8 0

4 years ago

Read 2 more answers

An archaeologist finds a 1.62kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i

Klio2033 [76]

Density equals Mass/Volume. The equation for this problem would be 1.62 kg/205 mL. If it’s easier, this can be converted to 1620 g/205 mL. The answer would be 7.902 (rounded to the nearest thousandth). Good luck!

5 0

4 years ago

Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4.

noname [10]

Answer:

$Y_A=92.1\%\\\\Y_B=89.6\%$

Explanation:

Hello there!

In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:

$m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2} *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4$

Now, we are able to compute the percent yields, by using the actual yield each scientist got:

$Y_A=\frac{83.67g}{90.9g} *100\%=92.1\%\\\\Y_B=\frac{81.35g}{90.9g} *100\%=89.6\%$

Regards!

8 0

3 years ago

A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?

sesenic [268]

The scale will read <u>112 grams.</u>

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

$ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g$

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

$PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)$

Hence, we can see that the scale will read <u>112 grams.</u>

Have a nice day!

7 0

4 years ago

Who were the scientists who won the nobel prize for the atomic model?

AleksAgata [21]

Answer:

Here's what I find.

Explanation:

Many scientists contributed to our model of the atom.

Among those who received the Nobel Prize for their work are:

1906 — J.J. Thomson — discovery of the electron

1908 — Ernest Rutherford — nuclear model of the atom

1922 — Niels Bohr — planetary model of the atom

1922 — Albert Einstein — quantum mechanical model of the atom

1935 — James Chadwick — discovery of the neutron

4 0

3 years ago