50 grams salt
Volume of 50 Grams of Salt
50 Grams of Salt =
2.78 Tablespoons
8.33 Teaspoons
0.17 U.S. Cups
0.14 Imperial Cups
Volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.
<h3>What are volatile substances?</h3>
Volatile substances are substances which can easily vaporize or change to gaseous state.
Volatile substances can either be solids or liquids but are mostly liquids.
Example of volatile substances include ether, petrol, chocolate.
The presence of volatile substances can be detected by the gases they release which may have characteristic odors.
Therefore, volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.
Learn more about volatile compounds at: brainly.com/question/25403770
The plant that should be moved here to protect from malnourishment is plant 3. The correct option is C.
<h3>What is visible spectrum?</h3>
The visible light spectrum is the portion of the electromagnetic spectrum that can be seen by the human eye. Simply put, this range of wavelengths is known as visible light.
The visible spectrum, also known as the optical spectrum, is the portion of the electromagnetic spectrum whose radiation consists of photons capable of sensitizing a normal person's human eye. The corresponding visible light radiation range is identified.
That being said, plant 3 is situated in front of a green stained glass window.
Plants have chlorophyll pigment that reflects back green light, making green light less effective for photosynthesis and causing them to die as quickly as if they were kept in the dark.
Thus, the correct option is C.
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6. V = IR= 1.2×100= 120 V
i tried my best, hope it helps!
You need to use the % information to determine the empirical formula of the compound first.
The empirical formula is the simplest ratio of atoms in the molecule.
Then use the rest of the data to determine moles of gas, and use this to determine molar mass of gas...
Empirical formula calculations:
Assume you have 100 g, calculate the moles of each atom in the 100 g
moles = mass / molar mass
molar mass C = 12.01 g/mol
molar mass H = 1.008 g/mol
molar mass O = 16.00 g/mol
C = 64.9 % = 64.6 g
H = 13.5 % = 13.5 g
O = 21.6 % = 21.6 g
moles C = 64.6 g / 12.01 g/mol = 5.38 mol
moles H = 13.5 g / 1.008 g/mol = 13.39 mol
moles O = 21.6 g / 16.00 g/mol = 1.35 mol
So ratio of C : H : O
is 5.38 mol : 13.39 mol : 1.35 mol
Divide each number in the ratio by the lowest number to get the simplest whole number ratio
(5.38 / 1.35) : (13.39 / 1.35) : (1.35 / 1.35)
4 : 10 : 1
empirical formula is
C4H10O
Finding moles and molar mass calcs
Now, you know that at 120 deg C and 750 mmHg that 1.00L compound weighs 2.30 g.
We can use this information to determine the molar mass of the gas after first working out how many moles the are in the 1.00 L
PV = nRT
P = pressure = 750 mmHg
V = volume = 1.00 L
n = moles (unknown)
T = temp in Kelvin (120 deg C = (273.15 + 120) Kelvin)
- T = 393.15 Kelvin
R = gas constant, which is 62.363 mmHg L K^-1 mol^-1 (when your P is in mmHg and volume is in L)
n = PV / RT
n = (750 mmHg x 1.00 L) / (62.363mmHg L K^-1 mol^-1 x 393.15 K)
n = 0.03059 moles of gas
We know moles = 0.03509 and mass = 2.30 g
So we can work out molar mass of the gas
moles = mass / molar mass
Therefore molar mass = mass / moles
molar mass = 2.30 g / 0.03059 mol
= 75.19 g/mol
Determine molecular formula
So empirical formula is C4H10O
molar mass = 75.19 g/mol
To find the molecular formula you divide the molar mass by the formula weight of the empirical formula...
This tells you how many times the empirical formula fits into the molecular formula. Tou then multiply every atom in the empirical formula by this number
formula weight C4H10O = 74.12 g/mol
Divide molar mass by formula weight empirical
75.15 g/mol / 74.12 g/mol
= 1
(It doesn't matter that the number don't quite match, they rarely do in this type of calc (although I could have made a slight error somewhere) but the numbers are very close, so we can say 1.)
The empirical formula only fits into the molar mass once,
molecular formula thus = empirical formula
<span>
C4H10O
Therefore, the </span>molecular formula of the compound is <span>C4H10O.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
