Answer:
(a) 22.3 torr; 5.6 torr; (b) 27.9 torr; (c) 77.7 % heptane; 23.3 % octane
(d) Heptane is more volatile than octane
Explanation:
We can use Raoult's Law to solve this problem.
It states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapour pressure of the pure component multiplied by its mole fraction. In symbols,
(a) Vapour pressure of each component
Let heptane be Component 1 and octane be Component 2.
(i) Moles of each component

(ii) Total moles

(iiii) Mole fractions of each component

(iv) Partial vapour pressures of each component

(b) Total pressure

(c) Mass percent of each component in vapour

The ratio of the mole fractions is the same as the ratio of the moles.

If we have 1 mol of vapour, we have 0.799 mol of heptane and 0.201 mol of octane

(d) Enrichment of vapour
The vapour is enriched in heptane because heptane is more volatile than octane.
Answer:
Grignard reagents are formed by the reaction of magnesium metal with alkyl or alkenyl halides. They're extremely good nucleophiles, reacting with electrophiles such as carbonyl compounds
Explanation:
hope this helps!
It depends on the mph
Please mark me as brainliest. I need brainliest to get to Ace (rank).
The answers that fit the blanks are SMALL and LITTLE, respectively. The particles or molecules or fas are small which makes it loose and easily moves around, and these only exert little attraction for other gas particles. The answer for this would be option D.
This is the balanced eq
N2 + 3H2 -> 2NH3
first you need to find mole of N2 by using
mol = mass ÷ molar mass.
mol N2= 20g ÷ (14.01×2)g/mol
=0.7138mol
then look at the coefficient between H2 and NH3.
it is N2:NH3
1:2
0.7138:0.7138×2
0.7138:1.4276 moles
moles of NH3 = 1.4276 moles