Answer:
The percentage loss in mass between sucrose solutions 0.5 mol/dm³ and 0.1 mol/dm³ is 80.0% loss in mass
Explanation:
The molecular formula of sucrose is C₁₂H₂₂O₁₁
The molecular mass of sucrose is 342.3 g/mol
Therefore;
The mass of sucrose in 0.1 mol/dm³ solution = 0.1 × 342.3 = 34.23 g
The mass of sucrose in 0.5 mol/dm³ solution = 0.5 × 342.3 = 171.5 g
The percentage loss in mass of the sucrose is given as follows;
![Percentage \ loss \ in \ mass = \dfrac{Original \ mass - New \ mass}{Original \ mass } \times 100](https://tex.z-dn.net/?f=Percentage%20%5C%20loss%20%5C%20in%20%5C%20mass%20%3D%20%5Cdfrac%7BOriginal%20%5C%20mass%20-%20New%20%5C%20mass%7D%7BOriginal%20%5C%20mass%20%7D%20%20%5Ctimes%20100)
Therefore;
![Percentage \ loss \ in \ mass = \dfrac{171.5 - 34.23}{171.5} \times 100 = 80.04 \%](https://tex.z-dn.net/?f=Percentage%20%5C%20loss%20%5C%20in%20%5C%20mass%20%3D%20%5Cdfrac%7B171.5%20-%2034.23%7D%7B171.5%7D%20%20%5Ctimes%20100%20%3D%2080.04%20%5C%25)
Which gives, the percentage loss in mass between sucrose solutions 0.1 mol/dm³ and 0.5 mol/dm³ is 80.0% to three significant figures.
These are always that B. nonhuman life in an urban ecosystem differs from that in an undeveloped forest ecosystem. That is the correct answer.
The answer is (c.) a (alpha cells) in the pancreas will be producing glucagon.
When a person sleeps for more than eight hours, the alpha cells in the pancreas will start to produce glucagon. The glucagon is responsible for the increase in blood glucose level the opposite of insulin which decreases the level.
Exhaled air has a higher concentration of CO2 and the lungs are humidified within
Translation occurs on the surface of the
Ribosomes
This translations occurs in order to assemble a protein and the ribosomes are the organelle that assembles proteins