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diamong [38]
3 years ago
5

An oblique prism is created using rhombuses with edge lengths of 25 units. The area of one rhombus is 600 square units. The perp

endicular distance between the bases is 24 units.
What is the volume of the prism?
14,400 cubic units
15,000 cubic units
29,400 cubic units
36,000 cubic units
Mathematics
2 answers:
Nuetrik [128]3 years ago
7 0

Answer:

14,400 cubic units

Step-by-step explanation:

We are given that An oblique prism is created using rhombuses with edge lengths of 25 units.

Area of each rhombus  : 600 square units.

The perpendicular distance between the bases is 24 units.

Since volume = \text{Area of Base} \times Height

Area of Base = Area of one rhombus = 24 units

Height = 24 units .

So, volume of the prism = 600 \times 24        

                                       = 14400 units^3      

Hence the volume of prism is 14,400 cubic units  

                                                   

Anit [1.1K]3 years ago
5 0
Volume = area of base x perpendicular distance
= 600 x 24 = 14,400 cubic units
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Answer:

64 cherries

Step-by-step explanation:

Given that

There are 280 pieces of fruit in a fruit salad

There are twice as many raspberries as blueberries,

three times as many grapes as cherries,

and four times as many cherries as raspberries

We need to find out the number of cherries in the fruit salad

So,

Let us assume the blueberries be x

So, the raspberries be 2x

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And, grapes be 24x

Now

x + 2x + 24x + 8x = 280

35x = 280

x = 8

hence, the No of cherries in the salad

= 8 x

= 8(8)

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5 0
3 years ago
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a) 170.00 =8n -30

200= 8n

n = 200/8 = 25 items


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6 0
4 years ago
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-3x-(3x-1)=-4x-9 what is the answer​
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Step-by-step explanation:

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3 0
3 years ago
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4 0
3 years ago
Fizzy Waters has been involved in multiple lawsuits regarding the alkaline substance concentration in their product and getting
ser-zykov [4K]

Answer:

Step-by-step explanation:

For the sample, n = 12

Mean, x = (158.2 + 162.8 + 161.5 + 161.2 + 166.5 + 160.1 + 158.4 + 175.6 + 159.9 + 168.8 + 161.9 + 163.7)/12 = 163.22

Variance, s² = (summation(x - mean)²/n

Summation(x - mean)² = (158.2 - 163.22)^2 + (162.8 - 163.22)^2 + (161.5 - 163.22)^2 + (161.2 - 163.22)^2+ (166.5 - 163.22)^2 + (160.1 - 163.22)^2 + (158.4 - 163.22)^2 + (175.6 - 163.22)^2 + (159.9 - 163.22)^2 + (168.8 - 163.22)^2 + (161.9 - 163.22)^2 + (163.7 - 163.22)^2 = 273.5368

Variance, s² = 273.5368/12 = 22.79

This is a test for a single variance. We would set up the test hypothesis.

For the null hypothesis,

H0: σ² ≥ 25

For the alternative hypothesis,

H1: σ² < 25

The formula for determining the test statistic,x² is

x² = (n - 1)s²/σ²

Where n - 1 is the degree of freedom, df.

df = 12 - 1 = 11

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For a test of 90% reliability, Confidence level = 0.9

Cl = 1 - alpha(level of significance)

alpha = 1 - 0.9 = 0.1

The critical value from the chi-square distribution table is 17.28. Since 17.28 > 10.0276, we would reject the null hypothesis. Therefore, the filling machine does not need repair because the variance of the process is not more than 25 oz.

8 0
3 years ago
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