The name is Aluminum Cloride
Answer:
The chemist would require to use 43.43 grams.
Explanation:
In order to solve this problem we need to know<u> how much do 0.550 moles of selenium weigh</u>. To do that we use selenium's<em> molar mass </em>and multiply it by the given number of moles:
- 0.550 mol * 78.96 g/mol = 43.43 g
The chemist would require to use 43.43 grams.
Answer: Organisms breakdown __into smaller particles___ in order to produce__new compounds__?
Explanation:
branliest pls :)
Answer:
{1s^2 2s^2 2p^6} 3s^2 3p^4
{Ne}3s^2 3p^4
Explanation:
i didnt understand the rest of that but this is the e- configuration on top and the bottom is noble gas configuration