Answer:
<u>Question</u><u> </u><u>1</u><u>:</u>
<em>Answer</em><em>:</em><em> </em>M: (17 - 35) & (17 - 37), N:(8 - 18) (8 - 16) & (8 - 17)
• Isotopes are atoms of the same element with same atomic number but different mass numbers.
<u>Question</u><u> </u><u>2</u><u>:</u>
<em>Answer</em><em>:</em><em> </em>Element M has high nuclear charge than element N
• Nuclear charge depends on atomic number or proton number.
Oxegan ........
explation :
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Taking into account the definition of density, the density of the sample is 0.5 .
It is necessary yo know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density allows you to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
In this case, you know:
Then, replacing in the definition of density:
Solving:
<u><em>density= 0.5 </em></u><u><em /></u>
Finally, the density of the sample is 0.5 .
Learn more about density:
Answer:
Explanation:
Mixing Ammonia gas into a solution of Copper(II) Sulfate will give Ammonium Sulfate and a precipitate of Copper(II) Hydroxide (Cu(OH)₂). The Ksp of Cu(OH)₂ is published => 2.2 x 10⁻²². Such gives a solubility* of the Cu(OH)₂ to be ~1.77 x 10⁻⁷M => [Cu⁺²] ~1.77 x 10⁻⁷M and [OH⁻] = 2(1.77 x 10⁻⁷)M = 3.53 x 10⁻⁷M. The reaction of Ammonium Hydroxide and Copper(II) Sulfate will generate 1 x 10⁻⁴ mole Cu(OH)₂ as a precipitate but only 1.77 x 10⁻⁷ mole of the hydroxide will remain in 1 Liter of solution b/c of extreme limited solubility.
*Solubility of 1:2 ionization ratio salts = CubeRt(Ksp/4).
Dilution law is given as:
(1)
where, = molarity of initial concentrated solution.
= volume of initial concentrated solution.
= molarity of final diluted solution.
tex]V_{2}[/tex] = volume of final diluted solution.
Volume of initial concentrated solution of = 100.0 mL
Molarity of initial concentrated solution of = 5.50 M
Volume of final diluted solution of = 0.950 M
Put the values in formula (1),
Hence, final diluted volume of the solution is .