<span>The purpose of washing the product with NaOH is simply to
neutralize any acid which remained or leaked after the 1st initial
separation. The NaOH base reacts with the acid to form neutralization reaction products
which are soluble in water.</span>
250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users
Answer:
first option is not true
Explanation:
1 mole = 6.02 × 10²³ particles
C3H8 has 1 mole, so has 6.02 × 10²³ particles
5O2 has 5 moles so 5 × 6.02 × 10²³ = 3.01 × 10²⁴ particles
3CO2 has 3 moles so 3 × 6.02 × 10²³ = 1.806 × 10²⁴ particles
4H2O has 4 moles so 4 × 6.02 × 10²³ = 2.408 × 10²⁴ particles
To reduce a haloalkane, it has to be eliminated first. This is because 2 bromopropanes are a saturated compound that can not be reduced by a saturated compound. Dehydrohalogenation of the haloalkanes into the form of propene and hydrogen bromide can lead to the elimination. The propene is then reduced to propane.