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seropon [69]
4 years ago
13

Q1. Why is Cl2 a nonpolar molecule, but HCl is a polar molecule? Explain your reasoning.​

Chemistry
1 answer:
notka56 [123]4 years ago
6 0

Answer:

\/\/

Explanation:

in CI2 the electron charge is identical on both atoms but on HCI electrons are shared unequally between the chlorine atoms and hydrogen atoms

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northern winds

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A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever
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What is the name of a solution whose concentration of solute is equal to the maximum concentration that
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g

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7 0
4 years ago
Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli
nikklg [1K]

88.98 %

The Balance Chemical Equation is as follow,

                                  2 HCl + Pb(NO₃)₂     →    2 HNO₃ + PbCl₂

According to equation,

          331.2 g (1 mole) Pb(NO₃)₂ produces  =  278.1 g (1 mole) PbCl₂

So,

                 870 g of Pb(NO₃)₂ will produce  =  X g of PbCl₂

Solving for X,

                     X  =  (870 g × 278.1 g) ÷ 331.2 g

                     X  =  730.5 g of PbCl₂

Therefore,

               Theoretical Yield =  730.5 g

Also as given,

                Actual Yield =  650 g

So using following formula for percentage yield,

                        %age Yield  =  (Actual Yield / Theoretical Yield) × 100

Putting values,

                        %age Yield  =  (650 g / 730.5 g) × 100

                        %age Yield  =  88.98 %

Brianliest please and thank you.

6 0
4 years ago
A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o
atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

C(s)+O_{2}(g)\rightarrow CO_{2}(g)

From the above balanced reaction, 1 mole of carbon releases 1 mole of CO_{2} gas.

Converting mass of charcoal into moles as follows:

n=\frac{m}{M}

Molar mass of pure carbon is 12 g/mol thus,

n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol

The same moles of CO_{2} is released. Converting these moles into mass as follows:

m=n×M

Molar mass of CO_{2} is 44 g/mol thus,

m=125mol\times 44 g/mol=5.5\times 10^{3}g

Converting mass into kg,

1g=10^{-3}kg

Thus, total mass of gas released is 5.5 kg.

7 0
3 years ago
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