The initial speed of the bullet = v₁= 511.07 m/s
<h3>Further explanation</h3>
Given
17.4 g bullet
5506 g wooden
The velocity of the block+bullet :1.61 m/s
Required
The initial speed
Solution
Momentum
m₁v₁+m₂v₂=m₁v₁'+m₂v₂'
v₂=0 ⇒block at rest
v₁'=v₂'=1.61 m/s
the equation becomes :
m₁v₁=(m₁+m₂)v'
17.4v₁=(17.4+5506)1.61
v₁= 511.07 m/s
Answer:
Explanation:
a ) In this case A rests on B and both rest on horizontal surface
Both moves together .
Total reaction due to weight of both of them
R = 1.2 + 3.6 = 4.8 N
friction force by horizontal surface = μ R , μ is coefficient of friction .
= .3 x 4.8 = 1.44 N
Force equal to frictional force will be required to put both of them in uniform motion .
b ) If A is held stationary , friction force will arise at both , the upper and lower surface of B .
At upper surface friction force = μ x weight of A
= .3 x 1.2 = .36 N
At lower surface friction force = μ x weight of A +B
= .3 x 4.8
= 1.44
Total frictional force on B
= 1.8 N N .
So 1.8 N force will be required to put B in uniform keeping A stationary.
Answer:
The time will be: 25.02 seconds
Explanation:
Given
A bicycle travels at a velocity of 2.33 m/s.
i.e.
and
- displacement = d = 58.3 m
As we know the formula to find the time
Time = Displacement/Velocity
= d/v
= 58.3/2.33
= 25.02 seconds
Therefore, the time will be: 25.02 seconds
Answer:
B
Explanation:
I am pretty sure it is B as the speed is obviously constant but the velocity is not constant as it defines as the rate of speed AND DIRECTION meaning that it is not constant as it always changes direction. And angular velocity is constant.