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4 years ago

A 10 N force is applied to a 2 kg mass, how fast will it be going in 10 seconds

1 answer:

5 0

Since
Force (weight) = mass x acceleration (gravity)

To determine acceleration, the formula will be:
Acceleration = Force / mass

Given are:
F = 10 N
M = 2kg
A = ?

Solution:

1. A = F/M
2. A = 10 kg*m/s2 / 2kg
3. A = 5 m/s2

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What is 404.2 rounded to the nearest ten thousandth?

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Answer:

The answer to your question is 404.2000

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4 years ago

A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt

Yuri [45]

The total power emitted by an object via radiation is:
$P=A\epsilon \sigma T^4$
where:
A is the surface of the object (in our problem, $A=1.25 m^2$
$\epsilon$ is the emissivity of the object (in our problem, $\epsilon=1$ )
$\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4)$ is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is $T=100^{\circ} C=373 K$

Substituting these values, we find the power emitted by radiation:
$P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW$
So, the correct answer is D.

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3 years ago

Which type of volcanic mountain has wide, gentle slopes?

myrzilka [38]

4) composite hope this helps u

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2 years ago

A bicyclist initially at rest, begins pedaling and gained speed steadily for 4.80s during which she covers 37.0m What was her fi

lidiya [134]

Answer:

The final speed of the bicyclist is 15.44 m/s.

Explanation:

Given;

initial velocity, u = 0

time of motion, t = 4.8 s

distance covered, d = 37.0 m

The acceleration of the bicyclist is calculated as;

d = ut + ¹/₂at²

37 = 0 + ¹/₂(4.8)²a

37 = 11.52a

a = 37 / 11.5

a = 3.22 m/s²

The final speed of the bicyclist is given as;

v² = u² + 2ad

v² = 0 + 2(3.22)(37)

v² = 238.28

v = √238.28

v = 15.44 m/s

Therefore, the final speed of the bicyclist is 15.44 m/s.

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3 years ago

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slavikrds [6]

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3 years ago