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Nataly [62]
3 years ago
10

Plz help help

Physics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

4

Explanation:

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A woman with a mass of 52.0 kg is standing on the rim of a large disk that is rotating at an angular velocity of 0.470 rev/s abo
Charra [1.4K]

Explanation:

It is given that,

Mass of the woman, m₁ = 52 kg

Angular velocity, \omega=0.47\ rev/s=2.95\ rad/s

Mass of disk, m₂ = 118 kg

Radius of the disk, r = 3.9 m

The moment of inertia of woman which is standing at the rim of a large disk is :

I={m_1r^2}

I={52\times 3.9^2}

I₁ = 790.92 kg-m²

The moment of inertia of of the disk about an axis through its center is given by :

I_2=\dfrac{m_2r^2}{2}

I_2=\dfrac{118\times (3.9)^2}{2}

I₂ =897.39 kg-m²

Total moment of inertia of the system is given by :

I=I_1+I_2

I=790.92+897.39

I = 1688.31 kg-m²

The angular momentum of the system is :

L=I\times \omega

L=1688.31 \times 2.95

L=4980.5\ kg-m^2/s

So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.

8 0
3 years ago
Responding to an alarm, a 765-N firefighter slides down a pole to the ground floor, 3.5 m below. The firefighter starts at rest
Afina-wow [57]

Answer:

Explanation:

Let acceleration of fall be a .

v² = u² + 2as

v = 3.8 m /s

u = 0

s = 3.5 m

3.8² = 0 + 2 x a x 3.5

a = 2.06 m /s²

Since this acceleration is less than g , an upward force is acting on the firefighter in the form of friction . Let this force be F . Let mass of the firefighter be m .

m = 765 / 9.8

= 78.06 kg

mg - F = ma

765 - F = 78.06 x 2.06

765 - F = 160.8

F = 604.2 N .

4 0
3 years ago
Which explains why conduction is unlikely when ice is placed on a freezer shelf? There is no direct contact. The ice is too cold
Ghella [55]

Answer: The ice and shel are at the same temperature.

Explanation: Conduction happens when you have two objects at different temperatures touching each other, in this case, the temperature flows from the hot object to the cold one, until the equilibrium is reached (this means that both objects are at the same temperature). So, in order to conduction to happen, we need a difference in temperature and direct contact. So there are two options of the given that can be the answer: "There is no direct contact" In the sentence says that "the ice is placed on the freezer shelf", so we have direct contact between both objects. "The ice and shelf are at the same temperature" Here both objects are inside of the freezer, so we can expect that both of them are at the same temperature, hence, there is no conduction.

5 0
3 years ago
Read 2 more answers
1. Consider the point exactly halfway between the two wires. Can you adjust the current so that, with current passing through ea
chubhunter [2.5K]

Answer:

hello your question is incomplete attached below is missing part of the question

answer:

1 )  Magnetic field due to long current carrying wire : B = \frac{U_{0} I}{2\pi d}

Therefore the net magnetic field due the both wires ; B = B_{1} + B_{2} . when we adjust the current I_{1} = I_{2} then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

F = \frac{U_{0}I_{1}I_{2}   }{2\pi d }

Explanation:

1 )  Magnetic field due to long current carrying wire : B = \frac{U_{0} I}{2\pi d}

Therefore the net magnetic field due the both wires ; B = B_{1} + B_{2} . when we adjust the current I_{1} = I_{2} then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

F = \frac{U_{0}I_{1}I_{2}   }{2\pi d }

8 0
3 years ago
An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first
VMariaS [17]

Answer:

Explanation:

First, since the engineer is a slowpoke and he reacts a third of a second too late, the train will have 330 - 0.29*25 = 322,75 meters to stop. now, be x (with x>0) the deceleration value for which the train bumps at the car and stops, you have two conditions:

\left \{ {{25t-\frac12xt^2 = 322.75} \atop {0=25-xt}} \right.

First states how much space the train has to stop, and the second tetermines how fast it slows down.

Solving the second for t, substituting in the first, and solving for x gives you a value of approximately 1.94 m/s^2.

As usual, double check the calculations for yourself, it's always a good practice

3 0
3 years ago
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