Answer:
U = 25 J
Explanation:
The energy in a set of charges is given by
U = 
in this case we have three charges of equal magnitude
q = q₁ = q₂ = q₃
with the configuration of an equilateral triangle all distances are worth
d = a
U = k ( 
)
we substitute
15 = k q² (3 / a)
k q² /a = 5
For the second configuration a load is moved to the measured point of the other two
d₁₃ = a
The distance to charge 2 that is at the midpoint of the other two is
d₁₂ = d₂₃ = a / 2
U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})
U = k q² ( 
)
U = (kq² /a) 5
substituting
U = 5 5
U = 25 J
a because of the following rate I do not now I saw it on the other one
Answer: 70m
Explanation:
Given, 2 skaters, one with a mass of 60kg.
Another 75kg.
Distance is 14m.
Assuming the system centre if mass does not change, both skaters would meet at the centre of the mass
let the 60kg skater be xm away from the centre, then, the 75kg skater would be (14 - x)m away from the centre too
m1x + m2(14 - x) = 0
m1x + 14m2 - m2x = 0
60x + 14*75 - 75x = 0
60x - 75x + 1050 = 0
-15x + 1050 = 0
15x = 1050
x = 70
Thus, the distance the 65kg skater moves is 70m
The answer is <span>D- a motorcycle with a constant velocity.
Velocity is much more stable in terms of speed and distance that can be associated with the dynamics of equilibrium (balance) compared to speed alone. It brings the constant relationship between the two elements.
Speed is only focused on time of travel and not with direction. While acceleration does not show equilibrium but only a change in speed.
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