If the product of the present age of father and his daughter is 430 and the age of father was 4 times as old as his daughter is now, then the present age of father is 43 and the present age of daughter is 10.
Given that the product of the present age of father and his daughter is 430 and the age of father was 4 times as old as his daughter is now.
We are required to find the present age of the father and daughter.
Suppose the present age of the father is x.
Suppose the present age of his daughter is y.
We are given product of present ages be 430.
xy=430----------1
y=430/x
According to question,
x-3=4y
Put the value of y=430/x.
x-3=4*430/x
-3x=1720

x=(3±
)/2*1
x=3±
)/2
x=(3±83)/2
x=(3+83)/2
(Ignoring the negative value because the age cannot be negative as it is coming before the greater number)
x=43
y=430/x
y=430/43
y=10
Hence if the product of the present age of father and his daughter is 430 and the age of father was 4 times as old as his daughter is now, then the present age of father is 43 and the present age of daughter is 10.
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Answer:
C is true.
Step-by-step explanation:
If you look at the model, the middle line in the box means the median and it is 7 so yeah! Hope this helped! Good Luck! :)
Answer:
-1, 8 hope this helps good luck
Answer:
the final answer will be:
6x^3 -9
Answer:
BC = 40º
BMC = 40º
Step-by-step explanation: Since the measure the major and minor arcs add up to 360º, just subtract 320 from 360 to find BC which is 40º. <BMC is also 40º because the measure of the arc is equal to its corresponding angle.