Someone Please Help Me!!

When you divide a whole number by a fraction with a numerator of 1 how can you find the quotient

Mekhanik [1.2K]

You just take the denominator of the fraction used to divided the one and there is your answer. does this help

7 0

2 years ago

PLS HELP ME ASAP FOR ALL 6!! (SHOW WORK!!) + LOTS AND LOTS OF POINTS!!! *GIVING THANKS!!*

aleksandr82 [10.1K]

This is the answer for #1

4 0

2 years ago

If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?

Alisiya [41]

If $k$ is odd, then

$\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor$

while if $k$ is even, then the sum would be

$\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4$

The latter case is easier to solve:

$\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0$

which means $k=6$ .

In the odd case, instead of considering the above equation we can consider the partial sums. If $k$ is odd, then the sum of the even integers between 1 and $k$ would be

$S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)$

Now consider the partial sum up to the second-to-last term,

$S^*=2+4+6+\cdots+(k-5)+(k-3)$

Subtracting this from the previous partial sum, we have

$S-S^*=k-1$

We're given that the sums must add to $2k$ , which means

$S=2k$
$S^*=2(k-2)$

But taking the differences now yields

$S-S^*=2k-2(k-2)=4$

and there is only one $k$ for which $k-1=4$ ; namely, $k=5$ . However, the sum of the even integers between 1 and 5 is $2+4=6$ , whereas $2k=10\neq6$ . So there are no solutions to this over the odd integers.

5 0

2 years ago

Miquel created the table below to show how he uses the money he earns at work

lara [203]

Complete Question with table is attached

Answer:

Miguel will save money of $90 if he earns $120.00

Step-by-step explanation:

The figure attached clearly shows the ratio of his earnings and savings. We have to find what would be the savings amount if he earn $120.00. So, first we have to calculate the percentage of ratio of his earnings and savings. As per the data given in the figure,

If he earns $10.00, he saves $7.50, calculate %amount he saves as below,

$\frac{\$ 7.50}{\$ 10.00} \times 100=0.075 \times 100=75 \%$

Likewise, calculate for all given data. If he earns $50.00 then he saves $37.50

$\frac{\$ 37.50}{\$ 50.00} \times 100=0.75 \times 100=75 \%$

If he earns $150.00 and save $112.50,

$\frac{\$ 112.50}{\$ 150.00} \times 100=0.75 \times 100=75 \%$

So, from all above, it clearly tells that Miguel saves 75% of amount from his earnings. Now, given earnings as $120.00. By finding 75% of $120.00, we can find his savings in that amount. So,

$\frac{75}{100} \times \$ 120=0.75 \times 120=\$ 90$

6 0

2 years ago

Read 2 more answers

How much liquid does a fish tank holds

Eva8 [605]

Answer:

depends on the fish tank

Step-by-step explanation:

7 0

2 years ago