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ella [17]
3 years ago
10

Jeremy played two basketball games. He scored 6 fewer points in the second game than he scored in the first. He scored 24 points

in the second game. Which equation can be used to find how many points he scored in the first game?
Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

24 + 6

Step-by-step explanation:

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Solve this quadratic equation.<br> x2 + 5x + 3 = 0
Xelga [282]

Answer:

Step-by-step explanation:

2x+5x+3=0

7x+3=0

   -3   -3

   =0  =-3

7x=-3

-3/7=-0.42857142857

x=-0.42857142857

I think it is right

3 0
3 years ago
Suppose there are signs on the doors to two rooms. The sign on the first door reads "In this room there is a lady, and in the ot
9966 [12]

Answer:

The lady is on the second door

Step-by-step explanation:

we have that

The sign on the first door reads "In this room there is a lady, and in the other one there is a tiger"

The sign on the second door reads "In one of these rooms, there is a lady, and in one of them there is a tiger."

so

The sign on the second door is true

The sign on the first door is true or false

Since one of these signs is true and the other is false, the sign in the first door must be false

therefore

The lady is on the second door

5 0
4 years ago
Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!
Drupady [299]

Answer:

6

Step-by-step explanation:

f(6) = -6   this is the value when the x value is 6

g(5) = -5 this is the value when the x value is 5

4 * f(6) -6*g(5)

4*-6 - 6* -5

-24 + 30

6

5 0
3 years ago
Read 2 more answers
Solve for X kinda confused i don’t know what to do!!
sweet [91]

Answer:

16.9265381881

Step-by-step explanation:

Tangent = Opposite/Adjacent.

Thus, tan62 = x/9 --> tan62 = 1.88072646535, multiply by 9 to get x, 1.88072646535* 9 = 16.9265381881

7 0
3 years ago
Sasha performs an experiment. She chooses one marble from each of three sacks. The first sack has black (B) and white (W) marble
Paladinen [302]

Answer:

Option D is correct

Step-by-step explanation:

From the question, we have:

Sack\ 1: B, W

Sack\ 2: G, Y

Sack\ 3: S, R

Required

The tree diagram

The selection process is as follows:

Sack\ 1: B, W

Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y) -- i.e. we write sack 2 as a subset of 1

Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R)) -- i.e. we write sack 3 as a subset of 2

<em>The only tree diagram that illustrates this is: option D</em>

5 0
3 years ago
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