Boy that math stuff will kill a cracker
If we draw a rhombus OABC on a coordinate grid with one vertex at the point O (0,0)
and let its height be 1 then (using the Pythagoras theorem) the coordinates of the 4 points will be as follows:-
O = (0,0) , A = (1, 1), B = (sqrt2+ 1 , 1) , C = (sqrt2, 0)
Slope of the diagonal OB = 1 / (sqrt2 + 1)
Slope of the other diagonal AC = - 1 / (sqrt2 - 1)
Product of the slopes = - 1 / ( sqrt2 + 1)(sqrt2 - 1) = -1 / 1 = -1
This proves that the diagonals are perpendicular.
Answer: y = -6x + 2
m = y_2 - y_1
/ x_2 - x_1
-10 - 8
/ 2 - (-1)
= -18/3 = -6
m (slope) = -6
y = mx + b
y = -6x +b
Find b using (-1,8)
y = -6x +b
8 = -6(-1) + b
8 = 6 + b
-6 -6
2 = b
Final answer: y = -6x + 2
To check using one of the points: (-1,8) or (2,-10)
y = -6x + 2
-10 = -6(2) + 2
-10 = -12 + 2
-10 = -10
This is a true statement.
Answer:
Yes I believe so
Step-by-step explanation:
Answer:
∠K =24
∠L =66
Step-by-step explanation:
first you need to find X in order to solve.
since they are Complementary they add together to equal 90 degrees
so we can set them equal to 90
13x-1=90
13x=91
x=7
now we can plug them in!
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∠K = 3(7)+3 = 24
∠L =10(7)-4=66
