Write the quantities 3 x 10^-4 cm and 3 x 10^4 km in ordinary notation

1 answer:

6 0

To write quantities in ordinary notation, you need to notice the power of the exponent.
If the power is positive, then you move the decimal point to the right by the number the power in exponent tells you.
If the power is negative, then you move the decimal point to the left by the number the power in exponent tells you.

We have:
3 x 10^-4 : the power of exponent is negative, therefore, we will move the decimal point 4 places to the left.
3 x 10^-4 = 0.0003 km

3 x 10^4 : he power of exponent is positive, therefore, we will move the decimal point 4 places to the right.
3 x 10^4 = 30000 km

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Find the enthalpy of neutralization of HCl and NaOH. 87 cm3 of 1.6 mol dm-3 hydrochloric acid was neutralized by 87 cm3 of 1.6 m

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Explanation:

The reaction equation for the given reaction will be as follows.

$HCl + NaOH \rightarrow NaCl + H_{2}O$

Each mole of both HCl and NaOH gives one mole of water.

Also, it is given that 1 liter of NaOH and HCl solution contains 1.6 mol $dm^{-3}$ of NaOH (HCl).

It is known that 1 $cm^{3}$ = 0.001 liter. So, 87 $cm^{3}$ = 0.087 liter.

Hence, number of moles of water obtained from the given reaction are as follows.

0.087 liter × 1.6 mol = 0.1392 moles

No. of moles = $\frac{mass}{molar mass of water}$

0.1392 moles = $\frac{mass}{18 g/mol}$

mass = 2.5056 g

Now, volume of water present before the reaction is $2 \times 0.087$ liter = 0.174 liter or 0.174 Kg (as density is 1 $Kg/cm^{3}$ ) or 174 g (as 1 kg = 1000 g).