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4 years ago

During resperation______.

Chemistry

1 answer:

Vikki [24]4 years ago

4 0

D. oxygen is used to break down glucose into energy

Explanation:

During respiration, oxygen is used to break down glucose into energy:

C₆H₁₂O₆ + O₂ → CO₂ + H₂O + energy

In the process of respiration, oxygen gas combines with glucose to liberate energy.

Respiratory system in the body is responsible for the metabolic break down of food to provide energy for the working of the human body.
Chemical energy in glucose is broken down to produce other forms of energy most especially heat.
The by product is usually carbon dioxide and water vapor.

Learn more:

Respiration brainly.com/question/3447259

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Without the respiratory system your blood would be useless. The circulatory and respiratory systems work together to circulate blood and oxygen throughout the body

Explanation:

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3 years ago

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3 years ago

The solubility table helps predict the products of what kind of reactions?

Ganezh [65]

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3 years ago

A 6.35 l sample of carbon monoxide is collected at 55.0◦c and 0.892 atm. What volume will the gas occupy at 1.05 atm and 59.0◦c?

Sonja [21]

Answer : The final volume of gas will be, 5.46 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.892 atm

$P_2$ = final pressure of gas = 1.05 atm

$V_1$ = initial volume of gas = 6.35 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $55.0^oC=273+55.0=328K$

$T_2$ = final temperature of gas = $59.0^oC=273+59.0=332K$

Now put all the given values in the above equation, we get:

$\frac{0.892atm\times 6.35L}{328K}=\frac{1.05atm\times V_2}{332K}$

$V_2=5.46L$

Thus, the final volume of gas will be, 5.46 L

7 0

3 years ago

Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st

Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have reaction called halohydrin formation. This is a markovnikov reaction with anti configuration. Therefore the halogen in this case "Br" and the "OH" must have different configurations. Additionally, in this molecule both carbons have the same substitution, so the "OH" can go in any carbon.

Finally, in the product we will have chiral carbons, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0

3 years ago