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3 years ago

What is a dependent variable

Chemistry

2 answers:

Juliette [100K]3 years ago

7 0

The dependent variable is the variable that changes based on the independent variable (the manipulated variable).

SCORPION-xisa [38]3 years ago

6 0

Values of dependent variables depend on the values of independent variables. The dependent variables represent the output or outcome whose variation is being studied.

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hich of the following statements is not true for an exothermic reaction? Question 2 options: The products have a higher heat con

yKpoI14uk [10]

Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings.

3 0

3 years ago

What is the percent by mass of carbon in acetone, c 3 h 6 o?

Tatiana [17]

In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).

Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol

To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C= $( \frac{3(12 g/mol)}{3(12 g/mol)+6(1 g/mol)+16 g/mol} ) x 100%$
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%

5 0

2 years ago

Read 2 more answers

The feed to a batch process contains equimolar quantities of nitrogen and methane. write an expression for the kilograms of nitr

timama [110]

1) number of moles of N2 = n/2

2) Number of moles of CH4 = n/2

3) Total number of moles of the mixture = n/2 + n/2 = n

4) Kg of N2

mass in grams = number of moles * molar mass

molar mass of N2 = 2 * 14.0 g/mol = 28 g/mol

=> mass of N2 in grams = (n/2) * 28 = 14n

mass of N2 in Kg = mass of N2 in grams * [1 kg / 1000g] = 14n/1000 kg = 0.014n kg

Answer: mass of N2 in kg = 0.014n kg

3 0

3 years ago

What does 2Cl mean?

Nina [5.8K]

Answer: I think that you have to find it in your lesson

Explanation:

4 0

2 years ago

What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?

Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

$\Delta G= \Delta H-T\Delta S$

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

$\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol$

Therefore, the answer is C. 30 kJ .

Best regards!

4 0

2 years ago