A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.
<h3>How do we calculate volume?</h3>
Volume for the given equation will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ = molarity of KNO₃ = 2M
V₁ = volume of KNO₃ = 1mL
M₂ = molarity of final solution = 0.0080M
V₂ = volume of final solution = ?
On putting these values on the above equation, we get
V₂ = (2)(1) / (0.0080) = 250mL
Hence option (2) is correct.
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Answer:
Whether a solution is acidic or basic can be measured on the pH scale. When universal indicator is added to a solution, the color change can indicate the approximate pH of the solution. Acids cause universal indicator solution to change from green toward red. ... Acidic solutions have a pH below 7 on the pH scale.
Explanation:
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The empirical and molecular formulas will be 
and 
respectively.
<h3>Empirical and molecular formula</h3>
The compound contains C, H, and O.
C = 61.15/12 = 5.0958
H = 5.3/1 = 5.3
O = 31.55/16 = 1.9719
Divide by the smallest
C = 2.6
H = 2.7
O = 1
Thus, the empirical formula is
Empirical formula mass = (12x5) + (1x5) + 16x2 = 97
n = 152.15/97 = 2
The molecular formula is
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