All categories

3 years ago

Which of these materials is an example of a conductor? (of electricity)

2 answers:

4 0

Well its either A or D coz if u put like a live wire into water it eletrocutes everything in it but if you rub wool agaisnt a like balloon or something it creates static energy and friction sooo yea its probably the wool actually :)

Sidana [21]3 years ago

3 0

I think it would be wool fabric, D. Because when you get a piece of wool fabric and rub it against a balloon it creates static electricity. Hope I helped some :)

You might be interested in

Carbon monoxide and chlorine combine in an equilibrium reaction to produce the highly toxic product, phosgene (COCl2 ) CO(g) Cl2

Anuta_ua [19.1K]

Answer:

Reaction will proceed towards forward direction.

Explanation:

Balanced reaction: $CO+Cl_{2}\rightleftharpoons COCl_{2}$

Reaction quotient ( $Q_{c}$ ) for this reaction is represented as:

$Q_{c}=\frac{[COCl_{2}]}{[CO][Cl_{2}]}$

Here, [CO] = [ $Cl_{2}$ ] = 0.010 M and [ $COCl_{2}$ ] = 0.070 M

So, $Q_{c}=\frac{0.070}{(0.010)^{2}}$ = 700

As $Q_{c}$ > $K_{c}$ therefore reaction will proceed towards forward direction i.e. more $COCl_{2}$ will be produced.

8 0

3 years ago

Diet soda has a lower density than bottled water True False

Rus_ich [418]

The answer to the question is false

3 0

3 years ago

Read 2 more answers

In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

LiRa [457]

Answer: 1.14

Explanation:

$HCl+NaOH\rightarrow NaCl+H_2O$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M$

To calculate pH of gastric juice:

molarity of $H^+$ = 0.072

$pH=-log[H^+]$

$pH=-log(0.072)=1.14$

Thus the pH of the gastric juice is 1.14

3 0

3 years ago

What is the correct answer ??

Ber [7]

Answer:

[H_3 O^+] = 1.0 ×10^-13

Explanation:

If we multiply the left side we get, 1e - 13. We add 13 to the right side while subtracting the remaining value from the left side (H3O+) than combine like terms. As you will get pH = 13.00

7 0

3 years ago

Read 2 more answers

a sample of water with a mass of 648.00 kg at 298 K is heated with 87 kh of energy. the specific heat of water is 1 J-1 kg K-1.

Stels [109]

q = mCΔT

The correct specific heat capacity of water is <em>4.187 kJ/(kg.K)</em>.

ΔT = q/mC = 87 kJ/[648.00 kg x 4.187 kJ/(kg.K)] = 87 kJ/(2713 kJ/K) = 0.032 K

Tf = Ti + ΔT = 298 K + 0.032 K = 298.032 K

3 0

3 years ago

Read 2 more answers