No, because all multiples of 5 end with 5 or 0
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Answer:
there is not enough info to answer this
Step-by-step explanation:
1) factor the denominators: 2b/(b-1)2 - 2/ (b-1)2
2) MAKE SURE YOU HAVE A COMMON DENOMINATOR
3) combine the numerators: 2b-2/(b-1)2
4) distribute 2 from numerator: 2(b-1)/(b-1)2
5) simplify; answer is 2/(b-1)
Let U={q, r, s, t, u, V, W, X, Y, Z},
trapecia [35]
Answer:
Ooh is theis unions I did it but