PLS HELP ASAP ILL GIVE BRAINLKEST THANKS

TEA [102]

9514 1404 393

Answer:

970

Step-by-step explanation:

It turns out that the radical terms cancel, so the result is an integer. You can find the integer value using your calculator. It is ...

(5 +2√6)³ +1/(5 +2√6)³ = 970

_____

The cube of 'a' is ...

(5+2√6)³ = 5³ +3·5²·2√6 +3·5·(2√6)² +(2√6)³

= 125 +3·50√6 +3·120 +48√6

a³ = 485 +198√6

The reciprocal of this is ...

b³ = 1/a³ = 1/(485 +198√6) = (485 -198√6)/(485² -6·198²) = (485 -198√6)/1

b³ = 485 -198√6

Then the sum is ...

a³ +b³ = (485 +198√6) +(485 -198√6) = 970

6 0

3 years ago

What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?

iren2701 [21]

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

triangles

- The slant height of it = $\sqrt{(\frac{1}{2}b)^{2}+h^{2}}$ , where

b is the length of its base and h is the perpendicular height

- Its lateral area = $\frac{1}{2}.p.l$ , p is the perimeter of the base

and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = $\sqrt{(\frac{1}{2}b)^{2}+h^{2}}$

∴ l = The slant height of it = $\sqrt{(\frac{1}{2}.24)^{2}+5^{2}}$

∴ l = $\sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13$

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = $\frac{1}{2}.p.l$

∴ The lateral area = $\frac{1}{2}.(96).(13)$

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

4 0

3 years ago

Simplify, will give brainliest plus 50 points

Lelu [443]

Answer:

20. = 5(ab)^4 / 9mc^7

24. = 9c^4

Step-by-step explanation:

5 0

3 years ago

. Look at each equation and possible solution. Is the solution correct? Select Yes or No for

insens350 [35]

A. No B. No C. Yes I honestly don’t know if that’s 100% right tho

4 0

3 years ago

As Sales Manager for ISeeYou Productions, you are planning to review the prices you charge clients for television advertisement

aksik [14]

The development fee p can be modeled by the equation p=-400q+9600 where p is the price the company charges and q is the number of contracts they get. The total revenue R ISeeYou obtains by signing q contracts is found by using the function: $R(q)=-400q^{2}+9600q$ . The cost ISeeYou Productions can be found by using the following function: C(q)=800q+16000. The monthlhy profit of Express ISeeYou Productions if found with the next function: $P(q)=-400p^{2}+8800q-16000$ . ISeeYou should sign 2 or 20 contracts to break even.

a) In order to solve part a of the problem, we will suppose the price will have a linear relation with the amount of contracts they signed, so we need to find two points to build this function.

We know that when signing 6 contracts, the company charges $7,200, so our first point will be:

(6, 7200)

we also know that the company signs 14 contracts when they charge $4,000. So our second point is:

(14, 4000)

so we can use these points to find the slope of the line by using the

slope formula:

$m=\frac{p_{2}-p_{1}}{q_{2}-q_{1}}$

$m=\frac{4000-7200}{14-6}$

so the slope is:

m=-400

We can now use one of those points and the slope to find the function for the price, so we get:

$y-y_{1}=m(x-x_{1})$

$p-p_{1}=m(q-q_{1})$

if we used the point: (6, 7200) we get:

$p-7200=-400(q-6)$

which can now be simplified:

p=-400q+2400+7200

so the price function is:

p=-400q+9600

b) In order to find the revenue equation we need to multiply the price equation by the amount of contracts they signed in a month, so we get:

R(q)=pq

$R(q)=(-400q+9600)q$

$R(q)=-400q^{2}+9600q$

c) The cost can be found by adding the fixed cost and the variable cost, so we get:

C(q)=800q+16000

d) The profit is found by subtracting the montly cost from the monthly revenue, so we get:

P(q)=R(q)-C(q)

so

$P(q)=-400q^{2}+9600q-(800q+16000)$

so we can now simplify our function to get:

$P(q)=-400q^{2}+9600q-800q-16000$

$P(q)=-400q^{2}+8800q-16000$

e) In order to find the number of contracts for the company to break even, we need to find the q contracts that will give a profit of $0 so we set the function of the previous part of the problem equal to zero so we get:

$P(q)=-400q^{2}+8800q-16000$

$-400q^{2}+8800q-16000=0$