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worty [1.4K]
3 years ago
10

Karina and perry are cleaning up litter in the park for community service hours. Karina and perry both claim they have covered t

he greatest area. Who is correct? Use mathematical reasoning

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

Karina is correct

Step-by-step explanation:

<em>See attached</em>

<u>Area that Karina cleaned up:</u>

  • 1/2*(6-0)(9-2) = 1/2*6*7 = 21

<u>Area that Petty cleaned up:</u>

  • 2*9 = 18

As we see Karina cleaned up more area than Petty, so she is correct

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The average cost of living for a family of four in twelve different cities was found to be $65,351 with a standard deviation of
Andrej [43]

Answer:

$65,351+/-$3,661.73

= ( $61,689.27, $69,012.73)

Therefore, the 90% confidence interval (a,b) = ( $61,689.27, $69,012.73)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $65,351

Standard deviation r = $7,711

Number of samples n = 12

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

$65,351+/-1.645($7,711/√12)

$65,351+/-1.645($2,225.973962860)

$65,351+/-$3661.727168905

$65,351+/-$3,661.73

= ( $61,689.27, $69,012.73)

Therefore, the 90% confidence interval (a,b) = ( $61,689.27, $69,012.73)

6 0
3 years ago
If C is the current value and S is the starting value, write an
LekaFEV [45]
Is there a diagram with this question?
7 0
3 years ago
7x-9x=-36<br> (I know the answer but I’m not sure if I have the work right)
pav-90 [236]

Answer:

18, is your answer!

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to
mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, \mu = $23,500

Sample mean,\bar{x} = $24,500

Sample standard deviation,s = $2,800

Sample size, n =  146

Confidence interval:

\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}  

Putting the values, we get,

t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436

24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)

The confidence interval is (24116.3878,24883.6122).

5 0
2 years ago
an oil company drilled several walls.fifty wells, or 25%,produced oil.what was the total number of wells that were drilled
Phantasy [73]
25% is equal to 100/25=1/4

We can substitute this into an equation to get the total number of wells where n can be equal to the total number of wells.

1/4*n=50
n/4=50
n=50*4
n=200

The total number of wells that were drilled was 200.
6 0
2 years ago
Read 2 more answers
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