Question

G=4ca-3ba, find a Also plz show how u found the answer.

Answer 1

G=4ca-3ba <=> G=a(4c-3b)

                   <=> a=G/(4c-3b)

Answer 2

The value of $\text{a}$ is $\boxed{a = \frac{G}{{\left( {4c - 3b} \right)}}}.$

Further explanation:

Factors are the numbers that are multiplied together to obtain another number.

Perfect square is number that can be obtaining by squaring the number.

Explanation:

The given expression is $G = 4ca - 3ba.$

The factors of $4ca$ can be expressed as follows,

$\begin{aligned}A&= 4ca \\ &= 4 \times c \times a\\\end{aligned}$

The factors of $3ba$ can be expressed as follows,

$\begin{aligned}B&= 3ba\\&= 3\times b \times a\\\end{aligned}$

Take a as $\text{a}$ common factor from $4ca$ and $3ba.$

The value of $\text{a}$ can be expressed as follows,

$\begin{aligned}G&= a\left( {4c - 3b}\right)\\\frac{G}{{\left( {4c - 3b} \right)}}&= a\\\end{aligned}$

The value of a is $\boxed{a = \frac{G}{{\left( {4c - 3b} \right)}}}.$

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Number system

Keywords: expression, place value, base value, decimal expansion, whole number, natural number, division, multiplication, subtraction, solve the equation, solution, linear equation.