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Musya8 [376]
3 years ago
15

How much energy is required to heat 32.5 g of water from 34°C to 75°C

Chemistry
1 answer:
cluponka [151]3 years ago
5 0
<span>Q = mc (delta T)  =  32.5 x 1 x (75-34)  =  1332.5 cal</span>
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How are superheavy elements made?​
Julli [10]

Answer: Most methods for making new elements involve a cyclotron, which speeds up atoms to high velocities before they smash into other atoms—these atoms are usually of different elements. This causes the nuclei to combine, creating new heavier elements.

Explanation: How are superheavy elements made?​

3 0
2 years ago
What is the summary at the end of an experiment that explains the results
jasenka [17]

Answer:

The conclusion

Explanation:

6 0
3 years ago
The Valence Electrons of an Atom of Which Element would feel a Greater Effective Nuclear Charge than the Valence?
kumpel [21]
The effective nuclear charge is an innate property of a specific element. It is the pull of force that an electron feels from the nucleus. It is related to the valence electron by the equation: Z* = Z-S, where Z* is the effective nuclear charge, Z is the atomic number and S is the shielding constant.

For the following elements in the choices, these are their values of Z*:

Aluminum - +12.591
Beryllium - +1.912
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The effective nuclear charge of Boron is +3. Thus, the answers are  Aluminum and Carbon.
5 0
3 years ago
Heating by direct contact between particles is called ____________​
nataly862011 [7]

Answer:

conduction

Explanation:

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3 0
2 years ago
A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH
Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5    → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0
2 years ago
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