Answer: 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of
require = 1 mole of
Thus 0.061 moles of
will require=
of
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of
give = 1 mole of
Thus 0.061 moles of
give =
of
Mass of
Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.
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4. it remains in its initial phase
Reactant: <span>Cd(NO^3)^2+(aq)+H^2S(g)
</span>Product: <span>Cds(s)+2HNO^3(aq)</span>