The atomic number tells us the number of protons and electrons.
The atomic mass tells us the weight of the nucleus, which is the amount of protons and neutrons
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Answer:
Explanation:
Chromatography is a technique for the separation of a mixture by passing it in solution or suspension through a medium in which the components move at different rates.Chromatography is also used to help catch criminals.Spoilage detection. Chromatography can be used in flavor studies and to detect spoilage in foods. Used in additive detection and used in determining nutritional quality.
Answer :
The correct answer for primary component of phosphate buffer at pH = 7.4 is H₂PO₄⁻ and HPO₄²⁻ .
<u>Buffer solution :</u>
It is a solution of mixture of weak acid and its conjugate base OR weak base and its conjugate acid . It resist any change in solution when small amount of strong acid or base is added .
<u>Capacity of a good buffer : </u>
A good buffer is identified when pH = pKa .
From Hasselbalch - Henderson equation which is as follows :
![pH = pka + log \frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=pH%20%3D%20pka%20%2B%20log%20%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
If [A⁻] = [HA] ,
pH = pka + log 1
pH = pKa
This determines that if concentration of weak acid and its conjugate base are changed in small quantity , the capacity of buffer to maintain a constant pH is greatest at pka . If the amount of [A⁻] or [HA] is changed in large amount , the log value deviates more than +/- 1M and hence pH .
Hence Buffer has best capacity at pH = pka .
<u>Phosphate Buffer : </u>
Phosphate may have three types of acid-base pairs at different pka ( shown in image ).
Since the question is asking the pH = 7.4
At pH = 7.4 , the best phosphate buffer will have pka near to 7.4 .
If image is checked the acid - base pair " H₂PO₄⁻ and HPO₄²⁻ has pka 7.2 which is near to pH = 7.4 .
Hence we can say , the primary chemical component of phosphate buffer at pH = 7.4 is H₂PO₄⁻ and HPO₄²⁻ .
For the answer to the question above, <span>ater weights 1000kg per meter cubed. the volume of the pool is part A is 5*4*3 = 60 meters cubed </span>
<span>60*1000 = 60 000kg. the force from this is m*g = 60 000 * 9.81 = 588kN </span>
<span>part B: </span>
<span>volume: 4*4*3 = 48 meters cubed </span>
<span>48 * 1000 = 48000kg </span>
<span>F = 9.81*48000 = 470kN
I hope this helps.</span>