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Aleks [24]
3 years ago
15

If an object has an acceleration of 7 m/s, and a mass of 3 kg, what is its force?

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

force = 21 kg m/s^2 = 21 N

Step-by-step explanation:

If an object has mass (m)  3 kg, and its acceleration (a) is 7 m/s^2, its force is given by Newton's second law of motion: Force = M * a

Force = 3 kg * 7 m/s^2= 21 kg * m/s^2

This combinations of units (kg * m/s^2) is defined as Newtons in physics and abbreviated "N".

So we can say that the force on this object is of magnitude 21 N

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If a triangle has a base of 5 cm and a height of 6 cm what’s it’s area?
Margarita [4]

Answer:

the area is 30 you have to muiltly the two together

Step-by-step explanation:

4 0
3 years ago
Which of the following, if substituted for y, would make the following inequality a true statement? –14 < y – 12?
trasher [3.6K]
Any number that is larger than -2.
For example y=0
-14 < 0-12
= -14 < -12
3 0
3 years ago
What is the 214 term in the sequence 7,10,13,16?
mixer [17]
We can figure this out using the explicit formula.

f(n)=f(1)+d(n-1)

n represents the term we are looking for.
f(1) represents the first term in the sequence, which in this case, is 7.
d represents the common difference, which in this case, is +3.

f(n) = 7 + 3(n - 1)
f(n) = 7 + 3n - 3
f(n) = 4 + 3n

Now, we can input 214 for n and solve.

f(214) = 4 + 3(214)
f(214) = 4 + 642
f(214) = 646

The 214th term in this sequence is 646.
5 0
3 years ago
A gardener sold 72 apples from the crop which was 12 % of the total
Westkost [7]

Divide the number sold by the percentage:

72 / 0.12 = 600

Total crop was 600 apples.

7 0
3 years ago
Read 2 more answers
Don't get this
kap26 [50]
I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:

Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.

-- Their long sides are equal,  OA = OB, because both of those lines
are radii of the big circle.

-- Their short sides are equal, OC = OC, because they're both the same line.

-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.

-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)

These triangles are not congruent the way they are now, because one is
the mirror image of the other one.  But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.

So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
5 0
3 years ago
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