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worty [1.4K]
4 years ago
12

The potential difference between the plates of an air-filled parallel-plate capacitor with a plate separation of 4 cm is 51 V. W

hat is the magnitude of the electric field between the plates of this capacitor
Physics
1 answer:
Salsk061 [2.6K]4 years ago
6 0

Answer:

Explanation:

Electric field between plates of a parallel plate capacitor is uniform .

In a uniform electric field , relation between electric field and potential gradient is as follows

electric field = potential gradient               [ E = - dV / dl ]

in the given case ,

dV = 51 V  ,

dl = 4 cm

=  4 x 10⁻² m

E = 51 /  4 x 10⁻²

= 12.75 x 10² V / m

= 1275 V / m

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Air is heated in a glass bottle. The heat energy added to the air is 2.0 × 104 joules. What is the change in internal energy of
Liono4ka [1.6K]
The change in internal energy of the gas is \Delta U = 2.0 \cdot 10^4 J.

In fact, the 1st law of thermodynamics states that the change in internal energy of a system is equal to the amount of heat given to the system (Q) plus the work done on the system (W):
\Delta U = Q+W
In this example, no work is done on the bottle so W=0, while the heat given to the system is Q=2.0 \cdot 10^4 J, so the change in internal energy of the gas is
\Delta U = Q = 2.0 \cdot 10^4 J
4 0
3 years ago
If an object has a kinetic energy of 30 j and mass of 34kg how fast is the object moving ?
Murrr4er [49]

Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.

Ek = mv^2 / 2 — multiply both sides by 2

2Ek = mv^2 — divide both sides by m

2Ek / m = V^2 — switch sides

V^2 = 2Ek / m — plug in values

V^2 = 2*30J / 34kg

V^2 = 60J/34kg

V^2 = 1.76 m/s — sqrt of both sides

V = sqrt(1.76)

V = 1.32m/s (roughly)

5 0
3 years ago
A telephone pole has three cables pulling as shown from above, with F⃗ 1=(300.0iˆ+500.0jˆ) , F⃗ 2=−200.0iˆ , and F⃗ 3=−800.0jˆ .
Ray Of Light [21]

A) Net force in component form: F=100.0i-300.0j

B) Magnitude of the net force: 316.2, direction: -71.6^{\circ}

Explanation:

A)

The three forces given in this problem are:

F_1=300i+500j

F_2=-200i

F_3=-800 j

The three forces are given in component form, where the components with unit vector i is the component along the x-direction, while the components with unit vector j is the component along the y-direction.

In order to find the net force in component form, we just need to add the components of the three forces along each direction. Therefore:

- Along the x-direction:

F_x = F_{1x}+F_{2x}+F_{3x}=300+(-200)+0=100

- Along the y-direction:

F_y=F_{1y}+F_{2y}+F_{3y}=500+0+(-800)=-300

So, the net force in component form is

F=100.0i-300.0j

B)

The magnitude of a vector F is given by Pythagorean's theorem:

|F|=\sqrt{F_x^2+F_y^2}

where in this problem,

F_x=100 is the x-component

F_y=-300 is the y-component

Substituting,

|F|=\sqrt{(100)^2+(-300)^2}=316.2

The direction instead is given by

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-300}{100})=-71.6^{\circ}

where the negative sign means the direction is below the positive x-axis.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

8 0
3 years ago
A 120.0 kg crate is placed on a 15.00°
Citrus2011 [14]

F = 2820.1 N

Explanation:

Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as

Fnet = ma = 0 (a = 0 no sliding)

= F - mgsin15°

= 0

or

F = mgsin15°

= (120 kg)(9.8 m/s^2)sin15°

= 2820.1 N

7 0
3 years ago
Please Help
musickatia [10]
The answer is C because <span>this movement is caused by the heat in Earth and creates </span>convection currents. <span>Convection currents in the asthenosphere cause movement of Earth's tectonic plates. </span> 
4 0
3 years ago
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