<span>The change in the electron's potential energy is equal to the work done on the electron by the electric field. The electron's potential energy is the stored energy relative to the electron's position in the electric field. Vcloud - Vground represents the change in Voltage. This voltage quantity is given to be 3.50 x 10^8 V, with the electron at the lower potential. The formula for calculating the change in the electron's potential energy (EPE) is found by charge x (Vcloud - Vground) = (EPEcloud - EPE ground) where charge is constant = 1.6 x 10^-19. Filling in the known quantities results in the expression 1.6 x 10^-19 (3.50 x 10^8) = (EPEcloud - EPEground) = 5.6 x 10^-11. Therefore, the change in the electron's potential energy from cloud to ground is 5.6 x 10^-11 joules.</span>
Answer:
For cast iron we have
![h = 0.92 m](https://tex.z-dn.net/?f=h%20%3D%200.92%20m)
For copper
![h = 1.05 m](https://tex.z-dn.net/?f=h%20%3D%201.05%20m)
For Lead
![h = 1.23 m](https://tex.z-dn.net/?f=h%20%3D%201.23%20m)
For Zinc
![h = 2.43 m](https://tex.z-dn.net/?f=h%20%3D%202.43%20m)
Explanation:
As we know that final speed of the block is calculated by work energy theorem
![W_f + W_g = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=W_f%20%2B%20W_g%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
now we have
![-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=-%5Cmu_k%20mg%20cos%5Ctheta%28%5Cfrac%7Bh%7D%7Bsin%5Ctheta%7D%29%20%2B%20mgh%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
now we have
![v^2 = 2gh - 2\mu_k g h cot\theta](https://tex.z-dn.net/?f=v%5E2%20%3D%202gh%20-%202%5Cmu_k%20g%20h%20cot%5Ctheta)
![v = \sqrt{2gh(1 - \mu_k cot\theta)}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gh%281%20-%20%5Cmu_k%20cot%5Ctheta%29%7D)
For cast iron we have
![4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.15cot52%29%7D)
![h = 0.92 m](https://tex.z-dn.net/?f=h%20%3D%200.92%20m)
For copper
![4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.29cot52%29%7D)
![h = 1.05 m](https://tex.z-dn.net/?f=h%20%3D%201.05%20m)
For Lead
![4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.43cot52%29%7D)
![h = 1.23 m](https://tex.z-dn.net/?f=h%20%3D%201.23%20m)
For Zinc
![4 = \sqrt{2(9.81)(h)(1 - 0.85cot52)}](https://tex.z-dn.net/?f=4%20%3D%20%5Csqrt%7B2%289.81%29%28h%29%281%20-%200.85cot52%29%7D)
![h = 2.43 m](https://tex.z-dn.net/?f=h%20%3D%202.43%20m)
Answer:
Velocity(v) = frequency(f) × wavelength
f = 0.3165
Wavelength = 2×length(L)
L = 157cm
Convert the length in centimetres to metre = 1.57m
v = 2×1.57 × 0.3165
v = 0.99m/s
Approx. 1m/s
Explanation:
The velocity of a wave is the product of its frequency and it's wavelength. The frequency is already known. The wavelength is the distance between two successive wave crests which is formed by sloshing water back and forth in the bath tub. Sloshing water to one end of the tub will produce a wave crest first at that end then the other completing a cycle. The wavelength will be twice the length of the bath tub as it is the distance that both crests are formed.
Wave crest is the highest point of a wave, and in this case is where the water rises to a high point in the bath tub
Answer:
189 m/s
Explanation:
The pilot will experience weightlessness when the centrifugal force, F equals his weight, W.
So, F = W
mv²/r = mg
v² = gr
v = √gr where v = velocity, g = acceleration due to gravity = 9.8 m/s² and r = radius of loop = 3.63 × 10³ m
So, v = √gr
v = √(9.8 m/s² × 3.63 × 10³ m)
v = √(35.574 × 10³ m²/s²)
v = √(3.5574 × 10⁴ m²/s²)
v = 1.89 × 10² m/s
v = 189 m/s
72 m/s
Explanation:
Given,
Frequency ( f ) = 6 Hz
Wavelength ( λ ) = 12 m
To find : -
Speed ( v ) = ?
Formula : -
v = f x λ
v
= 6 x 12
= 72 m/s
Therefore,
the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m is 72 m/s.