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QveST [7]
3 years ago
7

A baseball with a mass of 0.15 kilograms collides with a bat at a speed of 40 meters/second. The duration of the collision is 8.

0 × 10-3 seconds. The ball moves off with a speed of 50 meters/second in the opposite direction. What is the value of the force?
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer: 1687.5 N

Explanation:

From the second law of motion given by Newton, Force is the rate change of momentum.

F = \frac{dp}{dt}=\frac {m dv}{dt} = \frac{m (v_f-v_i)}{dt}

Mass of the baseball, m = 0.15 kg

Initial velocity, v_i=-40 m/s (negative because direction of initial velocity is opposite to the final velocity)

Final velocity, v_f=50 m/s

The duration of collision, dt= 8.0 \times 10^{-3} s

Force, F = \frac{0.15 kg (50-(-40) m/s)}{8.0 \times 10^{-3} s}=1687.5 N

Hence, the value of force is 1687.5 N.

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       v₂ = 0.56 m / s

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This exercise can be done using Bernoulli's equation

        P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Where points 1 and 2 are on the surface of the glass and the top of the straw

The pressure at the two points is the same because they are open to the atmosphere, if we assume that the surface of the vessel is much sea that the area of ​​the straw the velocity of the surface of the vessel is almost zero v₁ = 0

The difference in height between the level of the glass and the straw is constant and equal to 1.6 cm = 1.6 10⁻² m

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