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3 years ago

6. Applying Explain how scientists see what early galaxies looked like..

1 answer:

6 0

Answer: The younger elliptical and lenticular galaxies had results similar to spiral galaxies like the Milky Way. The researchers found that the older galaxies have a larger fraction of low-mass stars than their younger counterparts.

Explanation:

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Which of the following is a scalar quantity?

makvit [3.9K]

The only scalar quantity is a. 35 m

Explanation:

In physics, there are two types of quantities:

- Scalar: a scalar quantiy is a quantity having only a magnitude, so it is just a number followed by a unit. Examples of scalar quantities in physics are:

Speed

Energy

Distance

Time

- Vector: a vector quantity is quantity having both a magnitude and a direction. Examples of vector quantities in physics are:

Velocity

Force

Acceleration

Displacement

Let's now analyze each given option, to evaluate if it is a scalar or a vector:

a. 35m --> it is only a unit (no direction), so it is a scalar

b. 20 m to the right --> it has a direction, so it is a vector

c. 30 m to the North --> it has a direction, so it is a vector

So, the only correct option is a).

Learn more about scalars and vectors:

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4 0

3 years ago

A scared elephant has a mass of 7000 kg. The mouse that frightened the elephant is 0.02 kg. The distance between the elephant an

arsen [322]

a. $9.34\cdot 10^{-9} N$

The gravitational force between two objects is given by:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

M,m are the masses of the two objects

r is the separation between the objects

In this problem, we have:

M = 7000 kg is the mass of the elephant

m = 0.02 kg is the mass of the mouse

r = 1 m is the separation

Substituting into the equation, we find the gravitational force exerted by the elephant on the mouse:

$F=(6.67\cdot 10^{-11}) \frac{(7000)(0.02)}{1^2}=9.34\cdot 10^{-9} N$

b. $-9.34\cdot 10^{-9}N$

We can solve this part by keeping in mind Newton's third law of motion, which states that:

"When an object A exerts a force (action) on object B, then object B exerts and equal and opposite force (reaction) on object A".

In our problem, we can identify the elephant as object A and the mouse as object B: this means that the gravitational force exerted by the elephant on the mouse is the action, while the gravitational force exerted by the mouse on the elephant is the reaction. The two forces are equal in magnitude and opposite in direction: therefore, the gravitational force exerted by the mouse on the elephant is equal to

$F=-9.34\cdot 10^{-9}N$

where the negative sign simply means that the direction is opposite.

6 0

3 years ago

PLEASE HELP! WILL REWARD BRAINLIEST

Doss [256]

The probablity is a 50 percent chance

3 0

3 years ago

On a cello, the string with the largest linear density (1.56 *10-2 kg/m) is the C string. This string produces afundamental freq

Mrrafil [7]

1) Wavelength of the wave: 1.6 m

2) Speed of the wave: 104.6 m/s

3) Tension in the string: 170.7 N

Explanation:

For the standing waves on a string, the wavelength of the wave is related to the length of the string by

$\lambda = 2 L$

where

$\lambda$ is the wavelength

L is the length of the string

For the string in this problem.

L = 0.8 m is its length (I assume there is a mistake in the text, since 0.08 m is not a realistic value for the length of the string)

Therefore, the wavelength of the wave on the string is

$\lambda=2(0.8)=1.6 m$

The speed of a wave is calculated through the wave equation:

$v=f\lambda$

where

f is the frequency

$\lambda$ is the wavelength

For the standing wave on this string, the fundamental frequency is

$f=65.4 Hz$

while the wavelength is

$\lambda=1.6 m$

Therefore, the speed of the wave is

$v=(65.4)(1.6)=104.6 m/s$

The speed of the wave is related to the tension in the string by

$v=\sqrt{\frac{T}{\mu}}$

where

v is the speed

T is the tension

$\mu$ is the linear density of the string

For this string,

v = 104.6 m/s

$\mu=1.56\cdot 10^{-2} kg/m$

Therefore, the tension in the string is

$T=\mu v^2 = (1.56\cdot 10^{-2})(104.6)^2=170.7 N$

Learn more about waves:

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8 0

3 years ago

a body is thrown vertically upward from the Earth's surface and it took 8 seconds to return to it's original position. find out

Georgia [21]

Answer:

v₀ = 39.2 m/s

Explanation:

Since the air resistance can be negligible, this object is in free-fall. Therefore, we can assume the acceleration is constant and is g = 9.8 m/s².

We know it takes the object 8 seconds throughout the entire flight, but since it is in free fall, we know that it took 4 seconds to reach the top of its trajectory, where the velocity is 0 m/s.

Now we have 3 known variables: time, final velocity, and acceleration. We can solve for initial velocity using this kinematic equation:

v = v₀ + at
where v = final velocity, v₀ = initial velocity, a = acceleration, t = time

Substitute known variables into the equation. Assume the positive direction is upwards and the negative direction is downwards.

0 = v₀ + (-9.8)(4)
0 = v₀ - 39.2
-v₀ = -39.2
v₀ = 39.2

The initial velocity of the body is 39.2 m/s.

---

You can also solve this question using the displacement of the body. Since it says the body returns to its original position, the displacement is 0 m. Now, you can use the total time, displacement, and acceleration (g) to solve for the initial velocity.

This equation relates all four of these variables:

Δx = v₀t + 1/2at²

Substitute all known variables into the equation.

0 = v₀(8) + 1/2(-9.8)(8)²
-8v₀ = -4.9(64)
-8v₀ = -313.6
v₀ = 39.2

The initial velocity is the same as we got before: 39.2 m/s.

So, depending on your preference, you can choose which equation to use. Either way, you'll get the same value for the initial velocity.

8 0

3 years ago